V = _____ x 10____

A box with mass 25.14 kg is sliding at rest from the top of the slope with height 13.30 m

lutik1710 [3]

Answer:

Explanation:

The first thing we are asked to find is the Force experienced by the box. That is found in the formula:

F - f = ma where F is the force exerted by the box, f is the friction opposing the box, m is the mass, and a is the acceleration (NOT the same as the pull of gravity). But F can be rewritten in terms of the angle of inclination also:

$wsin\theta-f=ma$ where w is the weight of the box. We will use this version of the formula because it will help us answer the second question, which is to solve for a. Filling in:

First we need the weight of the box. Having the mass, we find the weight:

w = mg so

w = 25.14(10) so

w = 251.4 N (I am not paying any attention at all to the sig fig's here, since I noticed no one on this site does!) Now we have the weight. Filling that in:

251.4sin(30) - f = ma Before we go on to fill in for f, let's answer the first question. F = 251.4sin(30) so

F = 125.7 And in order to answer what a is equal to, we find f:

f = μ $F_n$ where Fn is the weight of the object.

f = .25(251.4) so

f = 62.85. Filling everything in now altogether to solve for a, the only missing value:

125.7 - 62.85 = 25.14a and

62.85 = 25.14a so

a = 2.5 m/s/s

Now we have to move on to another set of equations to answer the last part. The last part involves the y-dimension. In this dimension, what we know is that

a = -10 m/s/s

v₀ = 0 (it starts from rest)

Δx = -13.30 m (negative because the box falls this fr below the point fro which it started). Putting all that together in the equation for displacement:

Δx = v₀t + $\frac{1}{2}at^2$ and we are solving for time:

$-13.30=0t+\frac{1}{2}(-10)t^2$ and

$t=\sqrt{\frac{2(-13.30)}{-10} }$ so

t = 1.6 seconds to reach the bottom of the slope from 13.30 m high.

3 0

3 years ago

A 97.3 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.67 r

Yuliya22 [10]

Answer:

w = 1.14 rad / s

Explanation:

This is an angular momentum exercise. Let's define a system formed by the three bodies, the platform, the bananas and the monkey, in such a way that the torques during the collision have been internal and the angular momentum is preserved.

Initial instant. The platform alone

L₀ = I w₀

Final moment. When the bananas are on the shelf

we approximate the bananas as a point load and the distance is indicated

x = 0.45m

L_f = (m x² + I ) w₁

angular momentum is conserved

L₀ = L_f

I w₀ = (m x² + I) w₁

w₁ = $\frac{I}{m x^2 + I} \ w_o$

Let's repeat for the platform with the bananas and the monkey is the one that falls for x₂ = 1.73 m

initial instant. The platform and bananas alone

L₀ = I₁ w₁

I₁ = (m x² + I)

final instant. After the crash

L_f = I w

L_f = (I₁ + M x₂²) w

the moment is preserved

L₀ = L_f

(m x² + I) w₁ = ((m x² + I) + M x₂²) w

(m x² + I) w₁ = (I + m x² + M x₂²) w

we substitute

w = $\frac{m x^2 +I}{I + m x^2 + M x_2^2} \ \frac{I}{m x^2 + I} \ w_o$

w = $\frac{I}{I + m x^2 + M x_2^2} \ w_o$

the moment of inertia of a circular disk is

I = ½ m_p x₂²

we substitute

w = $\frac{ \frac{1}{2} m_p x_2^2 }{ \frac{1}{2} m_p x_2^2 + M x_2^2 + m x^2} \ \ w_o$

let's calculate

w = $\frac{ \frac{1}{2} \ 97.3 \ 1.73^2 }{ \frac{1}{2} \ 97.3 \ 1.73^2 + 21.9 \ 1.73^2 + 9.67 \ 0.45^2 } \ \ 1.67$

w = $\frac{145.60 }{145.60 \ + 65.54 \ + 1.958} \ \ 1.67$

w = 1.14 rad / s

5 0

3 years ago

A car's position in relation to time is plotted on the graph. What is the car's average velocity for segment C? A) -4 m/s B) -0.

kotegsom [21]

Answer:

b

Explanation:

its the anwser

7 0

3 years ago

Good Afternoon my son has a science project the category is Physical science can you'll give me science Ideas he can do I'm New

Naddik [55]

As a experiment you could use is The affect of light in plants. A study He can do is maybe about Gravity affects and how it works on weight. Also you can do a all time favorite the Mentos and Diet Coke Experiment.

Hopefully one of these ideas will inspire you!

7 0

4 years ago

Read 2 more answers

1. Three vehicles are traveling at the same speed in the same direction on a 1 point

rusak2 [61]

9514 1404 393

Answer:

The front of the black car

Explanation:

The position -21 is shown on the diagram at the front of the white van. The reference point is the position 0, which is shown on the diagram as the front of the black car.

4 0

3 years ago

Read 2 more answers

V = _____ x 10_____ m/s

V = _ x 10_ m/s