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vredina [299]
3 years ago
6

1. Three vehicles are traveling at the same speed in the same direction on a 1 point

Physics
2 answers:
rusak2 [61]3 years ago
4 0

9514 1404 393

Answer:

  The front of the black car

Explanation:

The position -21 is shown on the diagram at the front of the white van. The reference point is the position 0, which is shown on the diagram as the front of the black car.

Gre4nikov [31]3 years ago
3 0

Answer:

Explanation:

I'm answering this just so you can give the Brainliest to Squaredancefan, a master answerer in my opinion.

The reference point is where the 0 is. Everything to the right is positive and everything left of 0 is minus. 0 is the reference point because it is neither.

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If the humidity in a room of volume 410 m3 at 25 ∘C is 70%, what mass of water can still evaporate from an open pan? Express you
Keith_Richards [23]

Answer:

m=1864.68\ g

Explanation:

Given:

volume of air in the room, V=410\ m^3

temperature of the room, T=25+273=298\ K

<u>Saturation water vapor pressure at any temperature T K is given as:</u>

<u />p_{sw}=\frac{e^{(77.3450 + 0.0057\times T - \frac{ 7235}{T}  )}}{T^{8.2}}<u />

putting T=298 K we have

p_{sw}=3130\ Pa

<u>The no. of moles of water molecules that this volume of air can hold is:</u>

Using Ideal gas law,

P.V=n.R.T

n=\frac{P_{sw}.V}{R.T}

n=\frac{3130\times 410}{8.314\times 298}

n=518\ moles is the maximum capacity of the given volume of air to hold the moisture.

Currently we have 80% of n, so the mass of 20% of n:

m=(20\%\ of\ n)\times M}

where;

M= molecular mass of water

m=0.2\times 518\times 18

m=1864.68\ g is the mass of water that can vaporize further.

3 0
3 years ago
Tenemos un Cable de cobre de 1 km de longitud cuya sección es de 2 milímetros al cuadrado y queremos saber la resistencia que se
Nady [450]

Answer:

8.5 Ω

Explanation:

La resistencia de un material es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.

La fórmula de la resistencia (R) viene dada por:

R = ρL/A

Donde ρ es la resistividad del material, L es la longitud del material y A es el área de la sección transversal del material.

Dado que:

L = 1 km = 1000 m, A = 2 mm² = 2 * 10⁻⁶ m², ρ (cobre) = 1.7 * 10⁻⁸ Ωm

Sustituyendo da:

R = 1,7 * 10⁻⁸ * 1000/2 * 10⁻⁶

R = 8.5 Ω

7 0
3 years ago
A car travels 15 kilometers west in 10 minutes. After reaching the destination, the car travels back to the starting point, agai
jeka94

Speed = (distance traveled) / (time to travel the distance).
 
Strange as it may seem, 'velocity' is completely different. 

Velocity doesn't involve the total distance traveled at all. 
Instead, 'velocity' is based on 'displacement' ... the distance
between the start-point and end-point, regardless of the route
taken to get there.  So the displacement in driving once around
any closed path is zero, because you end up where you started. 

Velocity =

           (displacement during some time)
divided by
            (time for the displacement)

AND the direction from the start-point to the end-point.


For the guy who drove 15 km to his destination in 10 min, and then
back to his starting point in 5 min, (assuming he returned by way of
the same 15-km route):

         Speed = (15km + 15km) / (10min + 5min)  =  (30/15) (km/min)

                                                                                 =  2 km/min.

        Velocity = (end location - start position) / (15 min)  =  Zero .

5 0
3 years ago
In the ENGR 10 lab (E391), there are 50 long light bulbs (P=100 W) and 30 regular bulbs (P=60 W). How much energy is consumed li
Alenkinab [10]

Answer:

Total energy saving will be 0.8 KWH

Explanation:

We have given there are 50 long light bulbs of power 100 W so total power of 50 bulb = 100×50 = 5000 W = 5 KW

30 bulbs are of power 60 W

So total power of 30 bulbs = 30×60 = 1800 W = 1.8 KW

Total power of 80 bulbs = 1.8+5 = 6.8 KW

Total time = 3 hour

We know that energy E=power\times time=6.8\times 3=20.4KWH

Now power of each CFL bulb = 25 W

So power of 80 bulbs = 80×25 = 2000 W = 2 KW

Energy of 80 bulbs = 2×3 = 6 KWH

So total energy saving = 6.8-6 = 0.8 KWH

6 0
4 years ago
Two speakers both emit sound of frequency 320 Hz, and are in phase. A receiver sits 2.3 m from one speaker, and 2.9 m from the o
satela [25.4K]

Answer:

Option B

Explanation:

The phase difference is found by subtracting the 2.3m for the receiver from the other speaker which is 2.9m hence

Phase difference= 2.9-2.3= 0.6

3 0
3 years ago
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