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3 years ago

(NEED THE ANSWER AS SOON AS POSSIBLE)

Mathematics

2 answers:

Eddi Din [679]3 years ago

6 0

Answer: 42-8x

Step-by-step explanation:

Hi, to answer this question we have to write and equation for each girl.

The money left that Jessica has is equal to the money she had (15) minus the product of the number of apples bought (3) and the cost per apple(x):

Mathematically speaking:

Jessica = 15-3x

Same process for Levi:

Levi =27-5x

Adding both expressions:

15-3x+27-5x

15+27-3x-5x

42-8x

Feel free to ask for more if needed or if you did not understand something.

Naya [18.7K]3 years ago

5 0

Answer: 42 - 8x

Step-by-step explanation:

Here is the complete question:

Jessica had $15. She bought 3 apples for x dollars each. Levi had $27 and bought 5 apples for x dollars each. Which expression represents how much money both Jessica and Levi have left altogether?

Select one:

27 – 5x

42 – 8x

12 – 2x

39 – 3x

From the question, Jessica had $15. She bought 3 apples for x dollars each. This means she had:

15 - (3 × x) = 15 - 3x

Levi had $27 and bought 5 apples for x dollars each. Levi will have:

27 - (5 × x) = 27 - 5x

The amount they'll have altogether will be the addition of their amount left. This will be:

15 - 3x + 27 - 5x

= 15 + 27 - 3x - 5x

= 42 - 8x

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3 years ago

Place the following steps in order to complete the square and solve the quadratic equation, x^2 - 6x + 7 = 0.

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Answer:

option f

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option d

option c

option e

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Step-by-step explanation:

we have x^2 - 6x + 7 = 0

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3 years ago

Read 2 more answers

1. Type mmnn using exponents.

kompoz [17]

Step-by-step explanation:

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3 years ago

Read 2 more answers

Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mp

romanna [79]

Answer:

C. 210 miles

Step-by-step explanation:

We have been given that two cars leave Phoenix and travel along roads 90 degrees apart. Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mph.

We will use distance formula and Pythagoras theorem to solve our given problem.

$\text{Distance}=\text{Speed}\times \text{Time}$

$\text{Distance covered by Car 1 in 3.5 hours}=\frac{42\text{ Miles}}{\text{Hour}}\times \text{3.5 hour}$

$\text{Distance covered by Car 1 in 3.5 hours}=147\text{ Miles}$ .

Since car 1 leaves 30 minutes before car 2, so car 2 will travel for only 3 hours when car 1 will travel for 3.5 hours.

$\text{Distance covered by Car 2 in 3 hours}=\frac{50\text{ Miles}}{\text{Hour}}\times \text{3 hour}$

$\text{Distance covered by Car 2 in 3 hours}=150\text{ Miles}$

Since both car travel along roads 90 degree apart, therefore, the distance between both cars after Car 1 has traveled 3.5 hours would be hypotenuse with legs 147 and 150.

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