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daser333 [38]
4 years ago
8

8-

Mathematics
1 answer:
olchik [2.2K]4 years ago
8 0

Answer:

$45

Step-by-step explanation:

70 + -25 = 45

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HURRY !! I NEED THIS IN 10 mins
labwork [276]

Answer:

false

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the greatest common factor of 4p^4q^5 and 8p^3q^2​
Pani-rosa [81]

Answer:

4p^3q^2.

Step-by-step explanation:

The GCF of 4 and 8 is 8.

That of p^4 and p^3  is p^3,

and that of q^5 and q^2 is q^2.

So it is 4p^3q^2.

5 0
3 years ago
In the rectangle below, E1=2x -2, FH=3x+6, and m 4IHG =35°.Find Gl and m LIEH
Tpy6a [65]

Recall that the diagonals of a rectangle bisect each other and are congruent, therefore:

\begin{gathered} FH=2EI, \\ GI=EI. \end{gathered}

Substituting the given expression for each segment in the first equation, we get:

3x+6=2(2x-2).

Solving the above equation for x, we get:

\begin{gathered} 3x+6=4x-4, \\ 3x+6+4=4x, \\ 3x+10=4x, \\ 4x-3x=10, \\ x=10. \end{gathered}

Substituting x=10 in the equation for segment EI, we get:

EI=2*10-2=20-2=18.

Therefore:

GI=18.

Now, to determine the measure of angle IEH, we notice that:

\Delta HFG\cong\Delta GEH,

therefore,

\measuredangle GHF\cong\measuredangle HGE.

Using the facts that the triangles are right triangles and that the interior angles of a triangle add up to 180° we get:

m\measuredangle IEH=90^{\circ}-35^{\circ}=55^{\circ}.

<h2>Answer: </h2>\begin{gathered} m\operatorname{\measuredangle}IEH=55^{\operatorname{\circ}}, \\ GI=18. \\  \end{gathered}

4 0
1 year ago
Giving brainlist to whoever answers this question
Aleonysh [2.5K]

Answer:

44

Step-by-step explanation:

6x +22 + 7x + 16 = 90

13x +38 =90

13x = 52

x = 4

7 x 4 +16 = 44

3 0
3 years ago
Aidan has 20 ft of fence with which to build a rectangular dog run. What is the maximum area he can enclose? Enter your answer i
irina1246 [14]
<h2>Maximum area is 25 m²</h2>

Explanation:

Let L be the length and W be the width.

Aidan has 20 ft of fence with which to build a rectangular dog run.

         Fencing = 2L + 2W  = 20 ft

                     L + W = 10

                      W = 10 - L

We need to find what is the largest area that can be enclosed.

     Area = Length x Width

      A = LW

       A = L x (10-L) = 10 L - L²

For maximum area differential is zero

So we have

      dA = 0

      10 - 2 L = 0

        L = 5 m

      W = 10 - 5 = 5 m

Area = 5 x 5 = 25 m²

Maximum area is 25 m²

7 0
3 years ago
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