3088.22813276
hope this helps, you could've entered this into a calculator for next time.
(tanθ + cotθ)² = sec²θ + csc²θ
<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ
<u>Evaluate middle term</u>: 2tanθcotθ = 
= 2
⇒ tan²θ + 2+ cot²θ
= tan²θ + 1 + 1 + cot²θ
<u>Apply trig identity:</u> tan²θ + 1 = sec²θ
⇒ sec²θ + 1 + cot²θ
<u>Apply trig identity:</u> 1 + cot²θ = csc²θ
⇒ sec²θ + csc²θ
Left side equals Right side so equation is verified
Keenly snakelike smells an kelsmeml salesmen smell. Skkensens.
Answer:
False
Step-by-step explanation:
At sea level, elevation is 0. This means that we can portray sea level as being the midpoint of distances below sea level and distances above sea level.
Thus, a distance of 1 m below sea level = - 1 is equivalent to a distance of 1 m above sea level albeit in opposite directions.
Hence, an elevation of 15m above sea level is greater in distance Than an elevation of - 10 m below sea level because the absolute value of 15 is greater than the absolute value of 10.
|15 - 0|= 15
|-10 - 0| = 10
Hence, elevation of - 10 below Sea level is closer to sea level than elevation of 15 above sea level
Answer:
b= -60 or (0,-60)
Step-by-step explanation:
remember it is negative and it is on the y line!!
