First you do 2 times 2 which is 4 and then takeaway 1 of you answer which makes it
4
Answer:
t1= 1.1475 sec
t2=9.48 sec
Step-by-step explanation:
This question asking for the time when an object reach a specific height. I will explain what the formula stand for to make this easier.
h= height = 174feet
v0= initial velocity = 170 feet/s
t= time
h0= initial height= ground level = 0
The question have predetermined formula for the height, so we should use it instead of formula that involve gravity value.
h= -16 +v0t + h0t
174 feet = -16 + 170 feet/s x t + 0 x t
-16 + 170 feet/s x t - 174 feet = 0
8 - 85 feet/s x t + 87 feet = 0
This equation will be hard to solve since its value in fraction, so lets use the quadratic formula
t1=
t1= 1.1475
t2=
t2=9.48
There are three multiples of 6: 6, 12, 18.
There are two multiples of 7 and 8 each: 7, 8, 14, 16.
3+4=7, so the answer is 7/20 or C.
Answer:
2.5 km/s
Step-by-step explanation: