Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
120ft
Step-by-step explanation:
If the bases are 120ft apart from each other you would have to find the distance of going from first to second then to third. Then you divide it in half because you arent going around the diamond, you are cutting right through it.
Answer:
-72 X + 14
Step-by-step explanation:
Answer: B' (5,8), C' (3,1)
Step-by-step explanation:
You can use the points A' (-1,8) and A (-2,-3) to find how many units point A was translated.
-2 + 1 = -1
-3 + 11 = 8
Then, you simply add 1 to the x-values of points B and C and 11 to the y-values of points B and C to get B' (5,8), C' (3,1).
I hope this helps!
Use the rule of 3, note that we will convert the hours to minutes:
60 - 84
75 - x
(75 * 84) / 60 = x
6,300 / 60 = x
105 = x
105 minutes = 1h 45m
Hope it helped,
Happy homework/ study/ exam!
