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solong [7]
3 years ago
14

A study was conducted on the amount of time drivers wait for a stoplight to change at a particular intersection. The amount of t

ime spent by 300 drivers was recorded and the resulting data were used to create boxplot.
a. What is approximately the median amount of time spent at this traffic light?
b. The top 25% of drivers waited at least how long?
c. The mean amount of time spent at this traffic light was bigger or smaller than the median? Explain.

Mathematics
1 answer:
arlik [135]3 years ago
3 0

Answer:

a) Median amount of time that is spent is around 2.3, rounded to 2.

b) 4 unit time

c) Mean amount of time is bigger than the median.

Step-by-step explanation:

Find the given attachment.

Note: Complete Question, along with the diagram is added

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Initial salary =  $50,000 .

Rate of raise = 5% each year.

Therefore, each next year salary would be 105% that is 1.05 times.

5% of 50,000 = 0.05 × 50000 = 2500.

Therefore raise is $2500 each year.

According to geometric sequence first term 50000 and common ratio 1.05.

Applying geometric sequence formula

a_n = ar^{n-1}

1) a_n = 50000(1.05)^{n-1}

2) In order to find salary in 5 years we need to plug n=5, we get

a_5 = 50000(1.05)^{5-1}= 50000(1.05)^4

= 50000(1.21550625)

<h3>=$60775.3125.</h3>

3) In order to find the total salary in 10 years we need to apply sum of 10 terms formula of a geometric sequence.

S_n = \frac{a(1-r^n}{1-r}

Plugging n=10, a = 50000 and r= 1.05.

S_10 = \frac{50000(1-(1.05)^{10}}{1-1.05}

S_10 = \frac{50000(0.050)^{10}}{0.05}

= 628894.62678.

<h3>Therefore , you will have earned $ 628894.62678 in total salary by the end of your 10th year.</h3>



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