We are given 3 equations. Using these equations we can find f(h(2)).
h(x)=7x-5
h(2)=7(2)-5
h(2)=14-5
h(2)=9
f(x)=x^2-7
f(h(2))=(7x-5)^2-7
we know the answer for h(2) by now, so we can substitute for that.
f(9)=9^2-7
f(9)=81-7
f(9)=74
so f(h(2))=74
5x = 15
x = 3
3(3) - 5y = -16
9 - 5y = -16
5y = -16 - 9
5y = - 25
y = - 5
(3, -5)
Answer would be a (-1, ten-thirds) :)
Answer:
-502/3
Step-by-step explanation:
The answer is A)1/2[sin(4x)+sin(2x)]