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Elan Coil [88]
3 years ago
5

What is the solution to the system of equations below? y = negative one-fourth x + 2 and 3 y = negative three-fourths x minus 6

no solution infinitely many solutions (–16, 6) (–16, –2)
Mathematics
2 answers:
ValentinkaMS [17]3 years ago
8 0

Answer:

A: no solution

Step-by-step explanation:

I got it right on Edge

Arlecino [84]3 years ago
6 0

Answer:

no solution

Step-by-step explanation:

Suppose the system equations are:

y = (-1/4)x + 2   (1)

3y = (-3/4)x – 6    (2)

If we multiply equation (1) by 3:

3y = (-3/4)x + 6      (1)

3y = (-3/4)x – 6       (2)

then subtract it from equation (2):

0y = 0x – 12

0 = -12

This is not possible, therefore, the system equation has no solution

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Mary cut a wire into 7 equal pieces. The wire was originally 7.84 meters long. How long is each piece?
Dvinal [7]

Answer:

Each piece is 1.12 meters long

Step-by-step explanation:

7 equal pieces = divide x by 7

equation: 7.84 / 7

5 0
3 years ago
Find the y-coordinate of the y-intercept of the polynomial function defined below.
gayaneshka [121]
The y-intercept would be (0,8) because the last number on the equation, aka the c value, is you y-intercept.
5 0
2 years ago
Determine the numbers of solutions for 5x + 12 = 12x + 5.
mylen [45]

Answer:

Step-by-step explanation:

5x + 12 = 12x + 5

-7x + 12 = 5

-7x = -7

x = 1

one solution

8 0
3 years ago
Ariana buys an ant farm from a store near her home. The ant farm's price is $12 and the sales tax is 7%. What is the total price
FromTheMoon [43]

Answer: The total price for ant farm is $12.84

Step-by-step explanation:

The price of ant farm =  $ 12

The sales tax on the  price = 7%

Noe, 7% of $12 =

⇒The tax amount on the price = $0.84

So, the Taxed amount = The original price  + Tax

$ 12 + $0.84  = $12.84

Hence the total price for ant farm is $12.84

8 0
3 years ago
A survey said that 3 out of 5 students enrolled in higher education took at least one online course last fall. Explain your calc
marysya [2.9K]

Answer:

a) 60% probability that student took at least one online course

b) 40% probability that student did not take an online course

c) 12.96% probability that all 4 students selected took online courses.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they took at least one online course last fall, or they did not. The probability of a student taking an online course is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

3 out of 5 students enrolled in higher education took at least one online course last fall.

This means that p = \frac{3}{5} = 0.6

a) If you were to pick at random 1 student enrolled in higher education, what is the probability that student took at least one online course?

This is P(X = 1) when n = 1. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{1,1}.(0.6)^{1}.(0.4)^{0} = 0.6

60% probability that student took at least one online course.

b) If you were to pick at random 1 student enrolled in higher education, what is the probability that student did not take an online course?

This is P(X = 0) when n = 1.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{1,1}.(0.6)^{0}.(0.4)^{1} = 0.4

40% probability that student did not take an online course

c) Now, consider the scenario that you are going to select random select 4 students enrolled in higher education. Find the probability that all 4 students selected took online courses

This is P(X = 4) when n = 4.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.6)^{4}.(0.4)^{0} = 0.1296

12.96% probability that all 4 students selected took online courses.

3 0
3 years ago
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