What is the solution to the system of equations below? y = negative one-fourth x + 2 and 3 y = negative three-fourths x minus 6

Question

2 years ago

5

no solution infinitely many solutions (–16, 6) (–16, –2)

2 answers:

ValentinkaMS [17] · Answer 1 · 2022-07-14T16:47:15+03:00

8 0

Answer:

A: no solution

Step-by-step explanation:

I got it right on Edge

Arlecino [84] · Answer 2 · 2022-07-14T15:37:41+03:00

Answer:

no solution

Step-by-step explanation:

Suppose the system equations are:

y = (-1/4)x + 2 (1)

3y = (-3/4)x – 6 (2)

If we multiply equation (1) by 3:

3y = (-3/4)x + 6 (1)

3y = (-3/4)x – 6 (2)

then subtract it from equation (2):

0y = 0x – 12

0 = -12

This is not possible, therefore, the system equation has no solution