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Pachacha [2.7K]
3 years ago
5

which of the following are solutions to the quadratic equation check all that apply x ^ 2 + 10x + 25 = 7​

Mathematics
2 answers:
worty [1.4K]3 years ago
7 0

Answer: the answer is b and d

Step-by-step explanation:

Georgia [21]3 years ago
3 0

Answer:

the Answers are : B and E

Step-by-step explanation:

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Answer the question below. Be sure to show your work
likoan [24]

ANSWER:

We have to find new side-lengths of PQR triangle.

Original sides are.

\begin{gathered} PQ\text{ = 8cm} \\ QR=17\operatorname{cm} \\ RP=15\operatorname{cm} \end{gathered}

After multiplying by 2.5 we get

\begin{gathered} PQ^{\prime}=2.5\times PQ=(8\times2.5)cm=20\operatorname{cm} \\ QR^{\prime}=(17\times2.5)cm=42.5\operatorname{cm} \\ RP^{\prime}=(15\times2.5)cm=37.5\operatorname{cm} \end{gathered}

These are the new sides of the P'Q'R' triangle.

5 0
1 year ago
Samantha invested $40,500 at 6% to be compounded annually. What will be the value of Samantha's investment in 3 years? Round you
Anit [1.1K]

Answer:

7.45

Step-by-step explanation:

6 0
3 years ago
4 points
USPshnik [31]

Answer:

C $1.75

Step-by-step explanation:

$469 divided by 268 is $1.75, so it's $1.75 per item

5 0
3 years ago
How do I solve for x ?X +8=-15
DanielleElmas [232]
Subtract 8 from both sides
So you end up with x = -23
7 0
3 years ago
Read 2 more answers
A movie theater has a seating capacity of 387. The theater charges $5.00 for children, $7.00 for students, and $12.00 of
Rainbow [258]

Answer:

The attendance was 198 children, 90 students and 99 adults.

Step-by-step explanation:

We define:

c: children attendance

s: students attendance

a: adult attendance

The equation that describes the total ticket sales is:

5c+7s+12a=2808

We also know that the children attendance doubles the adult attendance:

c=2a

The third equation is the seating capacity, which we assume is full:

c+s+a=387

We start by replacing variables in two of the equations:

c=2a\\\\s=387-c-a=387-2a-a=387-3a

Then, we solve the remaining equation for a:

5c+7s+12a=2808\\\\5(2a)+7(387-3a)+12a=2808\\\\10a+(2709-21a)+12a=2808\\\\10a+12a-21a=2808-2709\\\\a=99

Then, we solve for the other two equations:

c=2a=2*99=198\\\\s=387-3a=387-3*99=387-297=90

The attendance was 198 children, 90 students and 99 adults.

8 0
4 years ago
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