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3 years ago

6. Erin wants to have more than $150 before she goes shopping for gifts for

Mathematics

1 answer:

murzikaleks [220]3 years ago

6 0

Answer: Erin needs to babysit for 20 hours in order for her to meet her goal.

Step-by-step explanation:

7.50h < 150 divide each side of the equation by 7.50

h=20

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How do I solve this

hichkok12 [17]

You wanna find a common denominator so put the problem like this

3 1/3.< You wanna take 3 (denominator)
And times it
By 5 then you wanna take the 5. - 2 2/5.< (deniminator) and times it by 3.
____ Your common denominator is 15

now it will look like this

3 1/15

-2 2/15
———-

Now subtract. You will need to borrow 1 from 3 since you cant subtract 2 by 1 so the 3 will become a 2 and the 1 will be come 11 and here you can subtract so this will be your answer.

2 11/15

-2 2/15
-———-
0 9/15

Thats your official answer 9/15 hope I helped :)

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3 years ago

What is the equation

Varvara68 [4.7K]

I bealive if it is the nature of the slope in unison comparing y-intercept elgebra it is Y=3x-3/4

8 0

3 years ago

Simplify.<br><br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B8%2B6%5E2%7D%7B11%7D%20" id="TexFormula1" title=" \frac{8+6^2}{

Romashka [77]

$\frac{8 + 6^2}{11} + 7 \times 2 \\ \\ \frac{8 + 36}{11} + 7 \times 2 \ / \ simplify \\ \\ \frac{44}{11} + 7 \times 2 \ / \ simplify \\ \\ 4 + 7 \times 2 \ / \ simplify \\ \\ 4 + 14 \ / \ simplify \\ \\ 18 \ / \ simplify \\ \\$

The final result is 18.

4 0

3 years ago

In a shipment of 22 smartphones, 2 are defective. How many ways can a quality control inspector randomly test 4 smartphones, of

Eddi Din [679]

Answer:

Therefore the required ways are =190

Step-by-step explanation:

Combination: Combination is the number of selection of items from a collection of items where the order of selection does not matter.

Total number of smartphones =22

Defective phone = 2

Non defective phone = (22-2) =20

The control inspector randomly test 4 smartphones of which 2 are defective.

Non defective phone = 2

The ways to select 2 non defective phone is

$^{20}C_2=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!}=\frac{19\times 20}{2} =190$

The ways to select 2 defective phone is= $^2C_2=1$

Therefore the required ways are = (190×1) =190

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4 years ago

What is the area of the figure? Round to the nearest tenth.

diamong [38]

Answer:

14.0 cm its a

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers