Answer:
461 adults and 864 students
Step-by-step explanation:
We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 1,325 tickets were purchased, then s+a=1325.
We also know that a total of $3,169 was collected and adult tickets cost $5 each and students cost $1 each. We can write 1s+5a=3169.
We will solve by substituting one equation into the other. We first solve the first equation for s which is s=1325-a. Substitute s=1325-a into 1s+5a=3169. Simplify and isolate the variable a.
1(1325-a)+5a=3169
1325-a+5a=3169
1325+4a=3169
1325-1325+4a=3169-1325
4a=1844
a=461
This means that 461 adults attended and 864 students attended since 864+461=1325.
Answer:
-2
Step-by-step explanation:
2x + y = 10 Subtract 2x from both sides.
2x-2x + y = 10 - 2x Combine the left.
y = 10 - 2x
The slope is the number in front of the x -- in this case - 2
The answer is - 2
I equals 70 grams cup because
The only restraints on profit result from the restriction on the domain which in turn place a restriction on profit.
0≤k. Knives sold cannot be negative.
So the range of profit or p is:
p=[-500, +oo)
Profit increases as the number of knives sold increases. $200 more profit is gained by each sale of a knife.
4000=200k-500
4500=200k
k=22.5
Since k is for knives sold, it must be an integer value, so a $4000 profit is not possible. At 22, p=3900 and at 23, p=4100
The gcf is 3 the lcm is 48 :^)
