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lianna [129]
3 years ago
14

If a population is

Mathematics
1 answer:
Kazeer [188]3 years ago
7 0

Answer:

D would be the answer Nonth grades at peak school

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The length of 2 sides on an isosceles triangle is 15. What is the range of possible lengths for the other leg?
erica [24]

Answer:

34

Step-by-step explanation:

4 0
3 years ago
Can someone please help me with my homework and explain it to me I will mark as brainlyist
Keith_Richards [23]

Answer:

121.76

Step-by-step explanation:

the original price is 83.97. you would have to find 45% of that. you would do this by putting x/83.97= 45/100

multiply 45 and 83.97 to get 3778.65. then divide that by 100 to get 37.7865. Add that to 83.97 to get 121.7565. round it to the nearest hundreth to get the total of 121.76 dollars

mark as brainlyest and answer my question

8 0
2 years ago
The graph of a function must be linear if it has what characteristic?
pantera1 [17]
The graph of a function is linear of the graph is a straight line.
3 0
3 years ago
Read 2 more answers
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
What is<br> (1/2)^2- 1/2 -6<br><br><br><br><br><br><br><br><br> .
N76 [4]

Answer:

-6.25 tI am not sure if this can help you but this is what I got

3 0
2 years ago
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