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Anna71 [15]
3 years ago
14

Please help AS LEVEL c2 tell me how to work out

Mathematics
1 answer:
Korolek [52]3 years ago
3 0
\bf [1-tan(\theta)][2sin(\theta)+1]=0\implies 
\begin{cases}
1-tan(\theta)=0\\\\
1=tan(\theta)\\\\
tan^{-1}(1)=\theta\\\\
\qquad \frac{\pi }{4},\frac{5\pi }{4}\\
----------\\
2sin(\theta)+1=0\\\\
2sin(\theta)=-1\\\\
sin(\theta)=\frac{-1}{2}\\\\
sin^{-1}\left(-\frac{1}{2}  \right)=\theta\\\\
\qquad \frac{7\pi }{6},\frac{11\pi }{6}
\end{cases}
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