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fiasKO [112]
3 years ago
11

Solve the following equations for x x(14-x) = 33

Mathematics
1 answer:
Katarina [22]3 years ago
7 0

ANSWER :

14x-x^2 = 33

Step-by-step explanation:

x(14-x) = 33

14x-(x)^2 = 33

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Can someone help me, ive been trying to figure this out for 30 minutes.
MAVERICK [17]

Answer:

6√5

Step-by-step explanation:

6 0
3 years ago
Find the final value and the compound interest if $8000 is invested for 2 years at 27% p.a.
gladu [14]

Answer:

$8000 / 2 = $4000 x 27 = $108000

Step-by-step explanation: i divided 8000 /2 then multiplied 27 to = 108000 I   hope this helps

8 0
2 years ago
the cost of an annual tuition at a university increased from 10,500 to 11,300 what is the percent increase in tuition to the nea
Maurinko [17]
Percent increase
find increase first
10500 to 11300
11300-10500=800
so
percent increase
change/original
origianal=10500
change=800
800/10500=8/105=0.0761
percent means parts out of 100
0.0761/1 times 100/100=7.61/100=7.61%

rond 7.61% to tenth or to 7.6%

7.6%

5 0
3 years ago
Replace ∗ with a monomial so that the derived equality will be an identity: (15y + ∗)2 = 225y2+12x3y+0.16x6
kobusy [5.1K]

Answer:

<u>∗ = 0.4x³</u>

Step-by-step explanation:

(15y + ∗)² = 225y²+12x³y+0.16x⁶

<u>Note:</u>

225y² = 15y * 15y = (15y)²

12x³y = 2 * 15y * 0.4x³

0.16x⁶ = 0.4x³ * 0.4x³ = (0.4x³)²

So, by factoring the right hand side:

225y²+12x³y+0.16x⁶ = (15y + 0.4x³)²

By comparing the left hand side with (15y + 0.4x³)²

<u>So, ∗ should be replaced with the monomial 0.4x³</u>

6 0
3 years ago
Please help! Area of part of a circle!!!
Helga [31]

The sector (shaded segment + triangle) makes up 1/3 of the circle (which is evident from the fact that the labeled arc measures 120° and a full circle measures 360°). The circle has radius 96 cm, so its total area is π (96 cm)² = 9216π cm². The area of the sector is then 1/3 • 9216π cm² = 3072π cm².

The triangle is isosceles since two of its legs coincide with the radius of the circle, and the angle between these sides measures 120°, same as the arc it subtends. If b is the length of the third side in the triangle, then by the law of cosines

b² = 2 • (96 cm)² - 2 (96 cm)² cos(120°)   ⇒   b = 96√3 cm

Call b the base of this triangle.

The vertex angle is 120°, so the other two angles have measure θ such that

120° + 2θ = 180°

since the interior angles of any triangle sum to 180°. Solve for θ :

2θ = 60°

θ = 30°

Draw an altitude for the triangle that connects the vertex to the base. This cuts the triangle into two smaller right triangles. Let h be the height of all these triangles. Using some trig, we find

tan(30°) = h / (b/2)   ⇒   h = 48 cm

Then the area of the triangle is

1/2 bh = 1/2 • (96√3 cm) • (48 cm) = 2304√3 cm²

and the area of the shaded segment is the difference between the area of the sector and the area of the triangle:

3072π cm² - 2304√3 cm² ≈ 5660.3 cm²

7 0
2 years ago
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