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77julia77 [94]
3 years ago
9

Solve the equation Axb by using the LU factorization given for A. Also solve Axb by ordinary row reduction. A ​, b Let Lyb and U

xy. Solve for x and y. nothing nothing Row reduce the augmented matrix and use it to find x. The reduced echelon form of is nothing​, yielding x nothing.
Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer: Hello your question is poorly written attached below is the complete question

answer:

y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right]

x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right]

Step-by-step explanation:

y = \left[\begin{array}{ccc}-4\\-11\\5\end{array}\right]

x = \left[\begin{array}{ccc}16\\12\\-40\end{array}\right]

attached below is the detailed solution using LU factorization

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When two quantities a,b are \textbf{directly} proportional, that means any change in a manifests a \textbf{direct} change (think "in the same direction") in b.

Silly example: "The more I eat, the fatter I get." Here the amount one eats is directly proportional to one's body weight.

This change isn't always one-for-one, so we introduce a constant k to account for any scaling that occurs on either variables behalf. In general, though, we can write a directly proportional relationship as a=kb.

Now, when a,b are \textbf{inversely} proportional, then a change in a manifests a change in b in the \textbf{inverse} (opposite) direction.

Silly example: "The more I eat, the less thin I get."

This time we write the relation as ab=k.

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