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2 years ago

A(-1,2) B(3,1) C(1,-4) To the new coordinated A'(-2,4) B'(6,2) C'(2,-8) what was the scale factor?

Mathematics

1 answer:

kicyunya [14]2 years ago

6 0

Answer:

Step-by-step explanation:

A(-1, 2) ==> A'(-2, 4)

B(3,1) ==> B'(6,2)

C(1,-4) ==> C'(2,-8)

Based on the results of each set, the scale factor is 2

A(-1*2, 2*2)= A'(-2, 4)

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balu736 [363]

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2 years ago

Find the smallest value of k such that the LCM of k and 6 is 60

Advocard [28]

Answer: The smallest valuest value for k is 10, such that LCM of k and 6 is 60.

Step-by-step explanation:

We know that, LCM = Least common multiple.

For example : LACM of 12 and 60 is 60.

If LCM of k and 6 is 60.

i.e. the least common multiple of k and 6 is 60.

Since, 10 x 6 = 60.

The smallest valuest value for k should be 10, such that LCM of k and 6 is 60.

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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madam [21]

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2 years ago

BD is the angle bisector of

AlexFokin [52]

Note: Let us consider, we need to find the $m\angle ABC$ and $m\angle DBC$ .

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The $m\angle ABC$ and $m\angle DBC$ .

Solution:

BD is the angle bisector of ABC. So,

$m\angle ABD=m\angle DBC$

$3x=x+20$

$3x-x=20$

$2x=20$

Divide both sides by 2.

$x=\dfrac{20}{2}$

$x=10$

Now,

$m\angle DBC=(x+20)^\circ$

$m\angle DBC=(10+20)^\circ$

$m\angle DBC=30^\circ$

And,

$m\angle ABC=(3x)^\circ+(x+20)^\circ$

$m\angle ABC=(4x+20)^\circ$

$m\angle ABC=(4(10)+20)^\circ$

$m\angle ABC=(40+20)^\circ$

$m\angle ABC=60^\circ$

Therefore, $m\angle DBC=30^\circ,m\angle ABD=30^\circ$ and $m\angle ABC=60^\circ$ .

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2 years ago