MrBillDoesMath!
Answer to #4: 81/256 * s^8 * t^ 12
Comments:
(7x^3) ^ (1/2) = 7 ^ (1/2) * x^(3/2) where ^(1/2) means the square root of a quantity. The answer written (7x^3) is NOT correct.
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(1) (27s^7t^11)^ (4/3)
= 27^(4/3) * (s^7)^(4/3) * (t^11)^ (4/3)
As 27 = 3^3, 27 ^(4/3) = 3^4 = 81
(2) (-64st^2)^ (4/3) = (-64)^(4/3) * (s^4/3) * t(^8/3)
As 64 = (-4)^3, (-64)^(4/3) = (-4)^4 = +256
So (1)/(2) =
81 * s^(28/3)* t^(44/3)
------------------------------- =
256 s^(4/3) * t^((8/3)
81/256 * s ^ (28/3 - 4/3) * t^(44/3 - 8/3) =
81/256 * s^(24/3) * t (36/3) =
81/256 * s^8 * t^ 12
MrB
Answer:
5?
Step-by-step explanation:
2x › 5 (buy at least 4)
so you can just start plugging numbers in.
I used 5, 5 times 2 is 10 which is 5 more that 5, which does met the quota.
2 inches in between each, start off on the edge go in 3 inches secound brace, than finsh on the final edge
To find expanded form, we need to split up the digits. When you do that, you take one digit and cut off everything to the left of it, then make everything to the right zeros.
We don't need to keep the zeros.
We can check this by adding the numbers back up to get 
.
Speed is computed by dividing total distance by total time.
Speed = Total Distance / total time
From the above formula, we can derive the formula of time and distance.
Time = Distance / Speed
Distance = Speed x time
