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3 years ago

Please help me quickly !!

Mathematics

1 answer:

Fittoniya [83]3 years ago

4 0

Answer:

1. multiply by 4/3

2. add 1.72

Step-by-step explanation:

1 you are cancelling out part of the first side making it x-1.72

2. adding 1.72 makes gets x by itself

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The cosine rule calculate tha angle of r 7.2 3,7 5.2

Leya [2.2K]

Given:

Consider the below figure attached with this question.

To find:

The measure of angle r by using the cosine rule.

Solution:

According to Law of Cosine,

$a^2=b^2+c^2-2bc\cos A$

Using the Law of Cosine, we get

$(7.2)^2=(3.7)^2+(5.2)^2-2(3.7)(5.2)\cos r$

$51.84=13.69+27.04-38.48\cos r$

$51.84=40.73-38.48\cos r$

$51.84-40.73=-38.48\cos r$

On further simplification, we get

$11.11=-38.48\cos r$

$\dfrac{11.11}{-38.48}=\cos r$

$-0.2887=\cos r$

$\cos^{-1}(-0.2887)=r$

$106.780143=r$

$r\approx 106.78$

Therefore, the measure of angle r is 106.78 degrees.

7 0

3 years ago

S+1/4s=-6-3/2<br> provide your answer

Ilya [14]

Answer:

s = -6

Step-by-step explanation:

Combining terms, we get ...

(5/4)s = -15/2

Multiplying by 4/5 gives ...

s = (4/5)(-15/2)

s = -6

8 0

4 years ago

a rectangle is 5 feet longer than it is wide. the perimeter of the rectangle is 34 feet. what is the length of the rectangle?

DochEvi [55]

The length is 11 feet and the width is 7 feet long

3 0

3 years ago

Read 2 more answers

Why is mental addition and subtraction important when you learn more difficult concept

Alex Ar [27]

It is important so you can be more fluent or faster in knowing bigger problems

7 0

4 years ago

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Beginning drivers soon learn that bringing an automobile to a stop requires greater distances for higher speeds. A formula that

BaLLatris [955]

The formula for the stopping distance in feet is

$d=1.1v+0.055v^2$

where $v$ = Speed of the car in miles per hour.

The stopping distance for the car traveling at 15 mph is

$d=1.1\times 15+0.055\times 15^2\\\Rightarrow d=28.875\approx 29\ \text{feet}$

The stopping distance for the auto traveling at 15 mph is $29\ \text{feet}$ .

The stopping distance for the car traveling at 30 mph is

$d=1.1\times 30+0.055\times 30^2\\\Rightarrow d=82.5\approx 83\ \text{feet}$

The stopping distance for the auto traveling at 30 mph is $83\ \text{feet}$ .

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4 0

3 years ago