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igomit [66]
3 years ago
12

Which of the following describes the function x^3-8

Mathematics
1 answer:
Dima020 [189]3 years ago
3 0

Answer:

Is there any options if so just repost with the options and i will answer it

Step-by-step explanation:

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The veloctiy of sound in air is given by the equation v=25 times the square root of 365+t where v is the velocity in meters per
Fed [463]

Answer:

c

Step-by-step explanation:

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3 years ago
G Am<br> 22<br> 10<br> 122<br> 19<br> 3<br> 34<br> Function in standard form
kotykmax [81]

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22+10+122+19+3+34

Step-by-step explanation:

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4 years ago
Which is more, 1 kilometer or 1,359 meters?
algol13

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1359 meters

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thenks and mark me brainliestt :))

7 0
3 years ago
Read 2 more answers
EXAMPLE 3 Show that the curvature of a circle of radius k is 1/k. SOLUTION We can take the circle to have center the origin, and
Anastasy [175]

Answer:

Therefore r'(t) =-k sin t i + k cos t j and |r'(t)| = k so T(t) = r'(t)/|r'(t)| = -sin t i + cos t j  and T'(t) = -cos t i- sin t j . This gives |T'(t)| = 1, so using this equation, we have κ(t) = |T'(t)|/|r'(t)| = 1/k.

Step-by-step explanation:

We are already given the definition of curvature and the parametrization needed to find the curvature of the circle. In genecral the curvature κ is equal to κ(t)=|T'(t)|/|r'(t)| where r(t) is a parametrization of the curve and T(t) is the normalized tangent vector respect to the parametrization, that is, T(t)=r'(t)/|r'(t)|.

Now, using the derivatives of sines and cosines, and the definition of norm,  we obtain that:

r(t) = k cos t i + k sin t j ⇒ r'(t)=-k sin t i + k cos t j ⇒|r'(t)|²=sin²t+cos²t=1

T(t) = r'(t)/|r'(t)|=-sin t i +cos t j ⇒ T'(t)= -cos t i - sin t j ⇒|T'(t)|²=cos²t+sin²t=1

6 0
4 years ago
Square root of x to the 24
nordsb [41]

Answer:

\sqrt{x} x24

Step-by-step explanation:

6 0
3 years ago
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