If you are multiplying by 100, the decimal will move 2 places to the right.
It moves to the right when multiplying because the number is getting greater, and there are 2 zeroes in 100 so it moves twice.
Answer:39
Step-by-step explanation:
Answer:
djchdjcycuchrivivurtiytvivytivi8fr cgdyhcd8w
4x + 1 → C
(f + g)(x) = f(x) + g(x) = 3x - 1 + x + 2 = 4x + 1
Answer:
Step-by-step explanation:
I used logic and took the easy way around this as opposed to the long, drawn-out algebraic way. I noticed right off that at x = -3 and x = -1 the y values were the same. In the middle of those two x-values is -2, which is the vertex of the parabola with coordinates (-2, 4). That's the h and k in the formula I'm going to use. Then I picked a point from the table to use as my x and y in the formula I'm going to use. I chose (0, 3) because it's easy. The formula for a quadratic is
![y=a(x-h)^2+k](https://tex.z-dn.net/?f=y%3Da%28x-h%29%5E2%2Bk)
and I have everything I need to solve for a. Filling in my h, k, x, and y:
and
and
-1 = 4a so
![a=-\frac{1}{4}](https://tex.z-dn.net/?f=a%3D-%5Cfrac%7B1%7D%7B4%7D)
In work/vertex form the equation for the quadratic is
![y=-\frac{1}{4}(x+2)^2+4](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B4%7D%28x%2B2%29%5E2%2B4)
In standard form it's:
![y=-\frac{1}{4}x^2-x+3](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B4%7Dx%5E2-x%2B3)