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3 years ago

14

Billy has a die. He rolls the die, and if the result is not even, he rolls the die

1 answer:

PIT_PIT [208]3 years ago

4 0

Answer:

1/4 is the answer.

Step-by-step explanation:

If he has a die then it is 6 sided. He has a 1/2 chance the 1st time that he gets a non-even number. The next time he also has a 1/2 chance of getting an even number so it's 1/2 times 1/2 = 1/4.

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Then number of pandas in the world is decreauing at a rate of

xxMikexx [17]

Answer:

2998 Panda's will be left in 4 years.

Step-by-step explanation:

0.5 x 4 =2

3000-2=2998

7 0

3 years ago

1.A clown made 3 times as many balloon hats as balloon dogs. He made 4 more balloon dogs than balloon swords.Write an algebraic

Dima020 [189]

Let x=balloon swords
let x+4=balloon dogs (four more than x is x+4)
let x+7=balloon hats (three more than x+4 is x+7)
the answer is x+7

I don't know how to correctly explain the second answer (although I do know that it is 1)

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3 years ago

In order to solve the equation −3x + 6 = 5, the first step is to

Angelina_Jolie [31]

The first step is to subtract 6 from both sides to cancel it out. You will be left with -3x= -1.

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3 years ago

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Hosting a breakfast brunch for 25 people, you plan to serve scrambled eggs. The grocery store sells eggs in cartons, and each ca

ratelena [41]

You need 7 cartons, 4•7=28 so you’ll be sure to have enough:)

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3 years ago

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andres has 4 bunches of balloons. there are 6 balloons in each bunchs how many balloons does andres have in all

Whitepunk [10]

$\large{|\underline{\mathtt{\red{G}\blue{i}\orange{v}\pink{e}\blue{n}\purple{}\green{}\red{↯}\blue{}\orange{}}}}$

1 bunch of balloons contain 6 balloons

$\large{|\underline{\mathtt{\red{T}\blue{o}\orange{\:}\pink{F}\blue{i}\purple{n}\green{d}\red{↯}\blue{}\orange{}}}}$

Number of balloons in 4 bunches = ?

$\large\underline{\underline{\maltese{\purple{\pmb{\sf{\: Solution :-}}}}}}$

<em>To</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>balloons</em><em> </em><em>in</em><em> </em><em>4</em><em> </em><em>bunches</em><em> </em><em>we</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>multiply</em><em> </em><em>the</em><em> </em><em>bumber</em><em> </em><em>of</em><em> </em><em>balloons</em><em> </em><em>in</em><em> </em><em>1</em><em> </em><em>bunch</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>bunches</em><em>.</em>

$\tt\multimap \: number \: of \: balloons \: in \: 1 \: bunch \times number \: of \: bunches$

$\sf \nrightarrow \: 6 \times 4 = 24$

➪ <em>T</em><em>h</em><em>u</em><em>s</em><em>,</em><em> </em><em>T</em><em>h</em><em>e</em><em>r</em><em>e</em><em> </em><em>a</em><em>r</em><em>e</em><em> </em><em>2</em><em>4</em><em> </em><em>b</em><em>a</em><em>l</em><em>l</em><em>o</em><em>o</em><em>n</em><em>s</em><em> </em><em>i</em><em>n</em><em> </em><em>4</em><em> </em><em>b</em><em>u</em><em>n</em><em>c</em><em>h</em><em>e</em><em>s</em><em>.</em><em>.</em><em>.</em><em>~</em>

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2 years ago

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