The surface

can be parameterized by

where

and

. Then the surface integral can be computed with

A = -0.7
B = -9/16 (0.5623)
C = -0.4
D = -5/16 (0.3125)
The last option is correct
Answer:
Step-by-step explanation:
i can not tell you are cheating on this that you are just geting good grads
Let

. Then

, and so as

, you have

. The limit is then equivalent to