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3 years ago

What is the length of a leg in a 45-45-90 triangle is the hypotenuse is 8

Mathematics

1 answer:

Gekata [30.6K]3 years ago

5 0

Answer:

The legs are both of length 4√2

Step-by-step explanation:

Let the length of one of the two equal legs be x. Then, by the Pythagorean Theorem, x^2 + x^2 = 8^2, or

2x^2 = 64, or x^2 = 32 = 2(16)

Solving for x, x = 4√2. The legs are both of length 4√2.

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A bus company charges $1.35 a kilometre for chartering a bus. Each bus can transport a maximum of 54 students. Assuming that the

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$1.25 is the answer in my opinion

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2 years ago

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Chord JK intersects chord ST at point L. Find the length of St. If necessary, round to the tenths place.

raketka [301]

Answer:

Step-by-step explanation:

The diagram is drawn and attached.

Using the intersecting chord theorem

SL X LT = JL X LK

x X 12 = 14(x-1)

12x=14x-14

12x-14x=-14

-2x=-14

x=7

Therefore:

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The correct option is C

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2 years ago

Which radical expressions are equivalent to 7 5/4

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Step-by-step explanation:

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2 years ago

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Lady bird [3.3K]

Answer:

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2 years ago

| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the

Westkost [7]

Answer:

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

Left Speed(km/h) Time

Car: 12PM X

Van: 12PM 60

Car/Van

DistanceCar AB + z

DistanceVan Az

Ratio: (AB+z)/Az = 7/5

Time until both meet = T (in hours)

Distance Car: xT

Distance Van: 60T

====

xT = AB + z

60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is: time (hr) = 108 km/(84 km/h)

time = 1.286 hours

Distance for at 1.289 hours is: distance (km) = (60 km/h)*(1.286 h)

distance = 77.14 km

At 1.286 hours, the car reverses direction. The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours. The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let t be the time after 1.286 hours that both vehicles meet/collide.

t*(60 km/h) + t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

==============

CHECK

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

YES

3 0

2 years ago