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Butoxors [25]
3 years ago
9

What is the solution to the inequality below? will give brainliest for correct answer

Mathematics
1 answer:
Mumz [18]3 years ago
7 0

Answer: A

Step-by-step explanation:

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Beth is going to enclose a rectangular area in back of her house. the house wall will form one of the four sides of the fenced i
Alina [70]

The maximum possible area would have a length of 24 feet and width of 12 feet.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depend on other variables while a dependent variable is a variable that depends on other variables.

Let x represent the length and y represent the width, hence:

Since beth has 48 ft fencing and cover 3 sides, hence:

x + 2y = 48  

x = 48 - 2y     (1)

Also:

Area (A) = xy

A = (48 - 2y)y

A = 48y - 2y²

The maximum area is at A' = 0, hence:

A' = 48 - 4y

48 - 4y = 0

y = 12 feet

x = 48 - 2(12) = 24

The maximum possible area would have a length of 24 feet and width of 12 feet.

Find out more on equation at: brainly.com/question/2972832

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7 0
1 year ago
For y = 6x + (-2) what is y when x = -1
PilotLPTM [1.2K]

Answer:

12

Step-by-step explanation:

6(-1)+(-2)

-6(-2)

12

I might be wrong so please forgive me if I am.

6 0
3 years ago
What a Expression that has a value -8
kirill [66]

Answer:

(-4+2*2)+8

Step-by-step explanation:

2*2=4

-4+4= 0

0+8= -8

5 0
3 years ago
Read 2 more answers
Whats 23/4 as a mixed fraction?
Misha Larkins [42]
The Answer is:
5 and 3/4
4 0
3 years ago
What is all of this <br> Identify ALL sets of parallel and perpendicular lines in this image.
Tamiku [17]

<u>Parallel lines</u> are lines that run side-by-side without touching or intersecting!

<u>Perpendicular lines</u> intersect/cross and can also make 90° angles (those little green boxes in the picture) in their corners!

Sets of parallel lines:

  • CD and EF

Sets of perpendicular lines:

  • CD and AB
  • EF and AB
5 0
2 years ago
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