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2 years ago

Determine 3rd term in the geometric sequence whose first term is -8 and whose common ratio is 6

Mathematics

2 answers:

k0ka [10]2 years ago

8 0

it would be -288. Correct answer

Brrunno [24]2 years ago

3 0

-8, -48, -288
or
-8, -4/3, -2/9

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Help please i don’t know how to do it

nekit [7.7K]

Answer:

x + 3y = 15

Step-by-step explanation:

Line is passing through the points $(3, \:4) = (x_1,\:y_1)\:and\: (9, 2)=(x_2,\:y_2)$

Slope of line (m)= (2 - 4)/(9 - 3) = -2/6 = -1/3

Equation of line in point-slope form is given as:

$y-y_1 =m(x-x_1)$

Plugging the values of $x_1,\: y_1\: and \: m$ in the above equation we find:

$y-4 =-\frac{1}{3}(x-3)$

$\implies 3y-12 =-x+3$

$\implies x+ 3y =12+3$

$\implies \huge {\orange{\boxed{x+ 3y = 15}}}$

This is the required equation of line in the form $\red{\bold{ax + by = c}}$

5 0

2 years ago

Find the area of the circle to the nearest tenth.<br> 8 cm

liraira [26]

Answer:

201.06.................

4 0

3 years ago

(-0.3) ÷ (-0.2)+(-2.56)<br><br><br> In whole numbers with steps please

Valentin [98]

Answer:

-1 to the nearest whole number.

Step-by-step explanation:

(-0.3) ÷ (-0.2)+(-2.56)

Order of operations - the division is done first:

= 1.5 = (-2.56)

= 1.5 - 2.56

= -1.06.

6 0

3 years ago

In each diagram, linek is parallel to line 1, and line t intersects lines k and l.

abruzzese [7]

Answer:

Step-by-step explanation:

7 0

2 years ago

Hakim deposited $50 in a saving account earning 10% interest, compounded annually . To the nearest cent , how much interest will

Paraphin [41]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$50\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}$

$\bf A=50\left(1+\frac{0.10}{1}\right)^{1\cdot 2}\implies A=50(1.1)^2\implies A=60.5 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{earned interest}}{60.5 - 50\implies 10.5}~\hfill$

7 0

3 years ago

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