Yeah there is a way... Lemme give a typical question...
Find the common difference of an arithmetic progression whose first term Is 1 and last term is 1023...
First term = T¹ =a
Last term = Tn = a + (n-1)d
Since your given the values of the first and the last term... You can substitute
Tn = 1 + (1023-1)d
1023 = 1 + 1022d
1022d = 1023 - 1
1022d = 1022
common difference = 1...
So there is a way....
You can get the common difference using the two terms given...
Hope this helped...
Answer:
o solve a logarithm, start by identifying the base, which is "b" in the equation, the exponent, which is "y," and the exponential expression, which is "x." Then, move the exponential expression to one side of the equation, and apply the exponent to the base by multiplying the base by itself the number of times indicated in the exponent
Step-by-step explanation:
hope it works
I think it's true because both opposite sides are always the same.
Answer:
A
Step-by-step explanation:
-When the function moves to the right or left to the x axis, the number has to be in "( )"
-If it moves to the right, you SUBTRACT the amount of units
-It it moves to the left, you ADD the amount of units.
So in this case, it is moving to the right 12 units so it is 
Answer:
Step-by-step explanation:
Since the lengths of the shelves are given in cm and the answer is to be expressed in cm, then let's convert the length of the whole board from 2.5 m to cm. Since there are 100 cm in a m, then multiply 2.5 by 100 to get 250 cm. Now let's start with the expressions for the shelves. The lengths of all the shelves are based on the length of the first shelf. You can usually tell which object is the main one because it is mentioned the most number of times. The first shelf is mentioned 3 times so that is the main shelf that the measurements of all the other shelves are based upon. Let's call the first shelf x. The second shelf is 18 cm longer than twice the length of the first so the second shelf is 2x + 18.
The third shelf is 12 cm shorter than the first so the third shelf is x - 12.
The last shelf is 4 cm longer than the first shelf so the last shelf is x + 4. Since he needs to use all 250 cm of the board, we add all the shelves together and set them equal to 250 cm:
x + 2x + 18 + x - 12 + x + 4 = 250 and
5x + 10 = 250 and
5x = 240 so
x = 48. The first shelf is 48 cm long. But we need the length of the second shelf. The expression for the second shelf is 2x + 18, so 2(48) + 18 = 114 cm.