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____ [38]
3 years ago
15

One week in the summer Hanna worked 5 days. Each day she earned $2 more than the previous day. She earned a total of $60. How mu

ch did she earn each day?
Mathematics
2 answers:
Alexeev081 [22]3 years ago
6 0

Answer:10$

Step-by-step explanation:

you have to times 5 and 2 u will get do$

Harman [31]3 years ago
3 0
Her starting earnings was $8 and every day there was an added 2 so 8+10+12+14+16=60
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Find the equation of the line that passes through the point (7,5) and is perpendicular to the line 2x - 3y=6
balu736 [363]
(7,5);\ \ \ \  2x - 3y=6 \ \ / subtract \ 2x \ from \ each \ side \\ \\-3y = -2x + 6\ \ /  divide \    each \term \ by \ (-3) \\ \\ y =  \frac{2} {3}x -2\\ \\ The \ slope \ is :m _{1} =  \frac{ 2}{3} \\ \\ If \ m_{1} \ and \ m _{2} \ are \ the \ gradients \ of \ two \ perpendicular \\ \\ lines \ we \ have \\\\\ m _{1}*m _{2} = -1

\frac{2}{3}\cdot m_{2}=-1\ \ / \cdot (\frac{3}{2})\\\\m_{2}=-\frac{3}{2}\\\\Now \ your \ equation \ of \ line \ passing \ through \ (7,5) would \ be: \\ \\ y=m_{2}x+b \\ \\5=-\frac{3}{2}\cdot 7  + b \\ \\ 5= -\frac{21}{2}+b\\ \\b=5+\frac{21}{2} \\ \\b= \frac{10}{2}+\frac{21}{2}\\ \\b= \frac{31}{2}\\\\b=15.5 \\ \\ y = -\frac{3}{2}x +15.5
8 0
3 years ago
I’ll give brainliest!!! Help pls
Shalnov [3]

Answer:

Tuesday

Step-by-step explanation:

8 0
3 years ago
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Find the slope and y-intercept of the line. 18x + 4y = 112
yan [13]
To find the slope and y-intercept, you can convert the linear equation into the form y = mx + b, where m is the slope and b is the intercept.
To do so, just simplify for y.
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y = - \frac{18}{4}x+28
So, the y-intercept is (0, 28) and the slope is 4.5.
Hope that helps!
4 0
4 years ago
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Juanita works at a telemarketing company. She makes 12 sales calls per hour. Employees are encouraged to make more than 480 call
sukhopar [10]
480 - 144 = 336
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ANSWER: 28 Hours
4 0
3 years ago
Water is leaking out of an inverted conical tank at a rate of 12,000 cm3/min at the same time that water is being pumped into th
Bas_tet [7]

Answer:

291111.1cm^3/min

Step-by-step explanation:

We are given that

\frac{dV}{dt}_{out}=12000 cm^3/min

Height of tank,h=6 m

Diameter of top,d=4 m

Radius,r=\frac{d}{2}=\frac{4}{2}=2 m

\frac{dh}{dt}=20 cm/min

\frac{r}{h}=\frac{2}{6}=\frac{1}{3}

r=\frac{1}{3} h

We have to find rate at which water is being pumped into the tank.

Volume of conical ,V=\frac{1}{3}\pi r^2 h

V=\frac{1}{3}\pi(\frac{1}{3} h)^2h=\frac{1}{27}\pi h^3

\frac{dV}{dt}=\frac{1}{9}\pi h^2(\frac{dh}{dt})

h=2 m=200 cm

1m=100 cm

\frac{dV}{dt}_{in}-12000=\frac{1}{9}\pi(200)^2\times 20

\frac{dV}{dt}_{in}=12000+\frac{1}{9}\pi (40000)\times 20

\frac{dV}{dt}_{in}=291111.1cm^3/min

4 0
3 years ago
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