S=zh−4zt3 ghfhh by tfde RV h
Answer:
Step 1 :
Split the figure into 3 parts
part 1: triangle with base = 7 + 2 + 6 = 15in, height = 7in
part 2 : Rectangle with breadth = 3 + 6 + 2= 11in and length 8in
Part 3 :Rectangle with breadth 2in and length 9in
Step 2 :
find the area of each part
Area of part 1

Area of part 2

Area of part 3

Total area = 52.5 + 88 + 18 = 158.5 sqaure inches
Answer:
The answer is D
Step-by-step explanation:
5 over 9 would be located in between 0.75 and 8 over 9
Answer:
To find area of the quadrilateral ABCD, now we have take the vertices A(x1, y1), B(x2, y2), C(x3, y3) and D(x4, y4) of the quadrilateral ABCD in order (counter clockwise direction) and write them column-wise as shown below. Add the diagonal products x1y2, x2y3, x3y4 and x4y1 are shown in the dark arrows.
Step-by-step explanation:
Step 1: 8|2x-1| = 12
step 2: 16x-8 = 12
step 3: 16x =12+8
step 4: 16x = 20
divide both sides by 16
step 5: x = 5/4 or 1 1/4