All categories

3 years ago

Ayuuuuuuddddaaaaaa!!!

Mathematics

1 answer:

Fofino [41]3 years ago

8 0

Answer:

Los triangulos son iguales porque tienen dos lados y el angulo comprendido respectivamente iguales, por tanto

$3x = x+8\\2x=8\\x=4\\$

You might be interested in

Help please 4 min please ASAP

guapka [62]

Answer:

Jared has 16 books.

Explanation: Subtract 28 by 12 and you'll get 16.

8 0

3 years ago

The height of a cylinder is twice the radius of its base.

Ber [7]

Let x represent radius of circle.

We have been given that the height of a cylinder is twice the radius of its base. So height of cylinder would be $2x$ .

Now we will use volume of cylinder formula to our given problem.

$V=\pi r^2h$ , where,

r = Radius of base of cylinder,

h = Height of cylinder.

Upon substituting our given values, we will get:

$V=\pi\cdot x^2\cdot 2x$

$V=2x^3\pi$

Therefore, our required volume expression would be $2x^3\pi$ .

6 0

3 years ago

Use the midpoint formula to estimate the sales of Cars, Inc. in 2009, given the sales in 2008 and 2010. Assume that the sales of

lana [24]

Answer:

<em>The estimated sales were $260 million</em>

Step-by-step explanation:

Assume the endpoints of a segment are (x1,y1) and (x2,y2).

The midpoint (xm,ym) is calculated as follows:

$\displaystyle x_m=\frac{x_1+x_2}{2}$

$\displaystyle y_m=\frac{y_1+y_2}{2}$

The sales ov Cars, Inc. were (2008,240 million) and (2010,280 million). We need to use the midpoint to estimate the sales in 2009:

$\displaystyle x_m=\frac{2008+2010}{2}=2009$

$\displaystyle y_m=\frac{240+280}{2}=260$

The estimated sales were $260 million

5 0

3 years ago

circle centered at the origin has a radius of 5 units. The terminal side of an angle, θ, intercepts the circle in Quadrant IV at

astraxan [27]

Answer:

Step-by-step explanation:

x²+y² = 5²

3²+y² = 25

y² = 16

y = ±√16 = ±4

Since the terminal side is in quadrant IV, y = -4

sinθ = -4/5

5 0

3 years ago

The parabola y=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class

oksano4ka [1.4K]

Y=(x-h)^2+k where (h,k) is the vertex

So, equation of new parabola is:

y=(x+1)^2+7

7 0

3 years ago