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kicyunya [14]
3 years ago
8

Read each verbal expression Then assign a variable and distribute

Mathematics
1 answer:
Rus_ich [418]3 years ago
7 0
6(14+x) for the first one i think
4(x+15) for the second one.
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Lian is deciding which of two gyms to join. Each gym charges a monthly rate plus a one-time membership fee.
BartSMP [9]
The conclusion is that both gym charge the same, because the identity 75 = 75 means that the two equations are equivalent (the same).
6 0
3 years ago
Read 2 more answers
How many permutations of three items can be selected from a group of six? Use the letters A, B, C, D, E, and F to identify the i
pishuonlain [190]

Answer:

In total, 120 permutations of three items can be selected from a group of six distinct elements.

In particular, there are 6 ways to order three distinct items.

\begin{aligned}\rm B-D-F \\ \rm B-F-D \\ \rm D-B-F \\ \rm D-F-B \\ \rm F-B-D \\ \rm F-D-B\end{aligned}.

Step-by-step explanation:

The formula \displaystyle P(n,\, r) = \frac{n!}{(n - r)!} = n \, (n - 1) \cdots (n - r + 1) gives the number of ways to select and order r items from a group of n distinct elements.

To select and order three items from a group six distinct elements, let n = 6 and r = 3. Apply the formula:

\begin{aligned} P(6,\, 3) &= \frac{6!}{(6 - 3)!} = \frac{6!}{3!} \\ &= \frac{6 \times 5 \times 4 \times 3\times 2 \times 1}{3 \times 2 \times 1} \\ &= 6 \times 5 \times 4 = 120 \end{aligned}.

In other words, there are 120 unique ways to select and order three items (select a permutation of three items) from a group of six distinct elements.

Consider: what's the number of ways to order three distinct items? That's the same as asking: how many ways are there to select and order three items from a group of three distinct elements? Let n =3 and r = 3. Apply the formula for permutation:

\begin{aligned} P(3,\, 3) &= \frac{3!}{(3 - 3)!} = \frac{3!}{0!} && \left(\text{$0! = 1$ by convention.}\right) \\ &= 3! = 3 \times 2\times 1 \\ &= 6\end{aligned}.

To find the permutations, start by selecting one element as the first of the list. A tree diagram might be helpful. Refer to the attachment for an example.

4 0
4 years ago
In a standard deck of cards what is the probability of choosing a red king replacing it and then choosing and then a club.
Vika [28.1K]

Answer:

1/104

Step-by-step explanation:

The probability of choosing a red king is 2/52 since there are only two red kings in a deck of 52 cards...the probability of choosing a club would be 13/52 since there are 13 club cardsin a deck of 52 cards

Therefore the probability of choosing both by replacing the king would be 2/52 × 13/52 giving us 1/104

3 0
2 years ago
I want to switch from online school to in-person school next school year and my mom wants to know why and I just think it would
Oliga [24]

Answer:

just tell her that you want to see your friends again or say that you think it will have a better effect on your grades. you could say that it would be eaiser to pay attention in class and that CV cases are droping so it would be still be safe to go.

Step-by-step explanation:

Hope this helps!

3 0
3 years ago
Read 2 more answers
Learning Task 1: Illustrate the following fractions on your notebook.
Marizza181 [45]

Answer:

The illustration is found in the attachment below.

<em>Note: The correct order of the question is found below:</em>

<em>Learning Task 1: Illustrate the following fractions on your notebook.</em>

<em>a.)2/3 b.)7/9 c.)10/12 d.)8/12 e.)4/5 f.) 8/6 g.)9/4 h.) 28/10</em>

Step-by-step explanation:

a) Draw a rectangle of sides 3 cm by 1 cm. Divide the rectangle into three equal parts. Shade two out of the three parts to give the fraction 2/3

b)  Draw a rectangle of sides 9 cm by 1 cm. Divide the rectangle into nine equal parts. Shade seven out of the nine parts to give the fraction 7/9

c)  Draw a rectangle of sides 12 cm by 1 cm. Divide the rectangle into twelve equal parts. Shade ten out of the twelve parts to give the fraction 10/12

d)  Draw a rectangle of sides 12 cm by 1 cm. Divide the rectangle into twelve equal parts. Shade eight out of the twelve parts to give the fraction 8/12

e)  Draw a rectangle of sides 5 cm by 1 cm. Divide the rectangle into five equal parts. Shade four out of the five parts to give the fraction 4/5

f)  Draw two rectangle of sides 6 cm by 1 cm. Divide the rectangles into six equal parts each. Shade all the six parts of the first rectangle completely. Then, shade two out of the six parts of the second rectangle to give the fraction 8/6

g) Draw three rectangles of side 4 cm by 1 cm. Divide each of the three rectangles into four parts each. Shade completely the four parts of the first and second rectangle. Then, shade one part out of the four parts of the third rectangle to give the fraction 9/4

h) Draw three rectangles of side 10 cm by 1 cm. Divide each of the three rectangles into ten parts each. Shade completely the ten parts of the first and second rectangle. Then, shade eight parts out of the ten parts of the third rectangle to give the fraction 28/10

6 0
3 years ago
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