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3 years ago

What is the perimeter of the rectangle JKLM

Mathematics

2 answers:

svlad2 [7]3 years ago

6 0

what is the perimeter of the rectangle JKLM

Vadim26 [7]3 years ago

4 0

Could you please upload a picture of the question?

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Find the measure of DC if m

kupik [55]

Answer:

B. 132°

Step-by-step explanation:

Find the measure of arc BD

m∠A = 1/2(arc BC - arc BD)
2*36° = 150° - arc BD
arc BD = 150° - 72° = 78°

Find the measure of arc DC

arc BD + arc BC + arc DC = 360°

arc DC = 360° - (150° + 78°) = 360° - 228° = 132°

Correct choice is B

7 0

3 years ago

Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm

VladimirAG [237]

Answer:

$y=2x^2-4x-8$

Step-by-step explanation:

Factored form of a parabola

$y=a(x-p)(x-q)$

where:

p and q are the x-intercepts.
a is some constant.

Given x-intercepts:

(1+√5, 0)
(1-√5, 0)

Therefore:

$\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))$

$\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})$

To find a, substitute the given point (4, 8) into the equation and solve for a:

$\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8$

$\implies a(3-\sqrt{5})(3+\sqrt{5})=8$

$\implies4a=8$

$\implies a=2$

Therefore, the equation of the parabola in factored form is:

$\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})$

Expand so that the equation is in standard form:

$\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)$

$\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)$

$\implies y=2(x^2-2x-4)$

$\implies y=2x^2-4x-8$

6 0

1 year ago

PLZZZ HURRY!

vfiekz [6]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Need help with questions 17 and 18

Pavlova-9 [17]

The answer to 17 is 18.6 and the 6 is repeating

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3 years ago

you own a house cleaning business. it takes you 2 hours and 45 minutes to clean a house. you have 3 houses to clean tomorrow. ho

lidiya [134]

495 minutes. Well you will have to work put how many hours that makesim sorry

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3 years ago