x + 3 < 4x - 12 or 4x - 12 < 20
<u>-x </u> <u> -x </u> <u> +12 </u> <u>+12 </u>
3 < 3x - 12 or 4x < 32
<u> +12</u> <u> +12 </u> <u> ÷4 </u> <u>÷4 </u>
15 < 3x or x < 8
<u> ÷3</u> <u>÷3 </u>
5 < x
5 < x < 8
Graph: 5 o---------------o 8
Answer:
0.30
Step-by-step explanation:
Probability of stopping at first signal = 0.36 ;
P(stop 1) = P(x) = 0.36
Probability of stopping at second signal = 0.54;
P(stop 2) = P(y) = 0.54
Probability of stopping at atleast one of the two signals:
P(x U y) = 0.6
Stopping at both signals :
P(xny) = p(x) + p(y) - p(xUy)
P(xny) = 0.36 + 0.54 - 0.6
P(xny) = 0.3
Stopping at x but not y
P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06
Stopping at y but not x
P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24
Probability of stopping at exactly 1 signal :
P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30
Answer:
25
Step-by-step explanation:
2+5=7
25 reversed is 52
52-25=27
£1.80 divided by 4 =0.45...
so the answer is 45p...
hope this helps and HAGD!!
