Answer:
$10 tickets = 1,119
$20 tickets = 1,310
$30 tickets = 893
Step-by-step explanation:
x = $10 tickets, y = $20 tickets, z = $30 tickets
10x + 20y + 30z = 64,180
x + y + z = 3,322
y = 191 + x
therefore;
10x + 20(191+x) + 30z = 64,180 eqn 1
x + (191 + x) + z = 3,322 eqn 2
make z the subject of eqn 2
z = 3,322 - x - (191 + x)
z = 3,322 - 191 - x - x
z = 3131 - 2x
put z in eqn 1
10x + 20(191+x) + 30(3131 - 2x) = 64,180
10x + 3820 + 20x + 93,930 - 60x = 64,180
10x + 20x - 60x = 64,180 - 3820 - 93,930
-30x = -33,570
x = 1,119
put x = 1,119 in z
z = 3131 - 2(1119)
z = 893
put x = 1,119 in y
y = 191 + 1119
= 1,310
10(1119) + 20(1310) + 30(893) = 64,180
1119 + 1310 + 893 = 3,322
