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eimsori [14]
3 years ago
13

-3w-3x-7w+4x-2w ......

Mathematics
2 answers:
Paul [167]3 years ago
6 0

Answer:

10w-7x-2w

Step-by-step explanation:

valkas [14]3 years ago
3 0

Answer:

− 1 2 +

Step-by-step explanation:

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3 years ago
Nick wanted to determine the length of one blade of a windmill. He stood at a point on the ground 440 feet from the windmill's b
mafiozo [28]

Answer:There are two right triangles. You need to find the opposite side (the height) of each of them. The difference between the two is the height of the blade, x.

You know the adjacent, 440, and you are looking for the opposite, so you need to use tan for both.

tan (30) = y / 440

y = 440 * tan (30) = 254.034...

tan (38.8) = z / 440

y = 440 * tan (38.8) = 353.769.--

353.8 - 254.0 = 99.8 = 100 feet.

Step-by-step explanation:

7 0
1 year ago
Please help with this question PLEASE!
yuradex [85]

Answer:

48 cm²

Step-by-step explanation:

The copper part is two equal triangles, find a triangle's area by counting squares and multiply by two.

Total copper=(Triangle area)(2)

=b(h)(½)(2)

=b(h)

=(6)(8)

=48 cm²

6 0
2 years ago
[6+4=10 points] Problem 2. Suppose that there are k people in a party with the following PMF: • k = 5 with probability 1 4 • k =
kirza4 [7]

Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

K people in a party with the following :

i). k = 5 with the probability of $\frac{1}{4}$

ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is  = 1 - P (none of the n born in the same month)

= 1 - P (choosing the n different months out of 365 days) = 1-\frac{_{n}^{12}\textrm{P}}{12^2}

1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)

= \frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})

= 0.25 \times 0.618056 + 0.25 \times 0.996132 + 0.5 \times 1

= 0.903547

2).P( k = 10|at least 2 share their birthday in same month)

=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

6 0
2 years ago
what is the probability of drawing a silver marble from a bag that contains 4 blue marbles, 7 silver marbles, and 5 green marble
umka21 [38]

Answer:

7 out of 16

Step-by-step explanation:

Well there are 16 marbles in total, and only 7 silver marbles. So the probability of getting a silver marble is 7/16

3 0
3 years ago
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