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seraphim [82]
3 years ago
11

What is the area of a circle with a radius of 42 in use 3.14 for pi

Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0

Answer: 5538.96

Step-by-step explanation: 3.14× 42×42

42×42=1764

∴ 3.14×1764= 5538.96

Vanyuwa [196]3 years ago
6 0

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<em>please</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> for</em><em> </em><em>full</em><em> solution</em><em> </em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

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How do you know if the factors will have negatives or positives in them?
harina [27]

When using factoring by grouping, the replacement terms will both have the same sign of the original middle term. If the last term is negative, then the signs of the factors will have one of each sign with the “stronger” number (the larger absolute value) matching the middle term. hope this helps
8 0
3 years ago
Simplify the expression.
Naddika [18.5K]

Answer:

3

Step-by-step explanation:

((7x-4)^2) - (7x-4)(7x-4) + 3

(7x-4)(7x-4) is 7x-4^2

So its (7x-4)^2 - (7x-4)^2 + 3

(7x-4)^2 cancel out.

Answer is 3

6 0
3 years ago
A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values ar
Kobotan [32]

Answer:

The coefficient of variation for the systolic measurements is 12.8 %

The coefficient of variation for the diastolic measurements is 16.3 %

Therefore, we can conclude that the systolic measurements are less dispersed as compared to diastolic measurements.

Step-by-step explanation:

The coefficient of variation is the ratio of standard deviation of the data to the mean of the data. It shows the dispersion in the data set.

Coefficient of variation for the systolic measurements:

Mean = μ = (120 + 128 + 156 + 98 + 154 + 122 + 118 + 136 + 128 + 120)/10

Mean = μ = 1280/10

Mean = μ = 128

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 16.4

Coefficient of variation = σ/μ

Coefficient of variation = 16.4/128

Coefficient of variation = 0.128

Coefficient of variation = 12.8%

Coefficient of variation for the Diastolic measurements:

Mean = μ = (79 + 76 + 75 + 51 + 92 + 87 + 59 + 64 + 72 + 81)/10

Mean = μ = 736/10

Mean = μ = 73.6

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 12

Coefficient of variation = σ/μ

Coefficient of variation = 12/73.6

Coefficient of variation = 0.163

Coefficient of variation = 16.3%

Conclusion:

We can conclude that the systolic measurements (12.8%) are less dispersed as compared to diastolic measurements (16.3%).

7 0
3 years ago
X to the power of 2 plus 25 equals 0
Natasha2012 [34]

Step-by-step explanation:

please give me brainlest

3 0
3 years ago
Read 2 more answers
Please help me out!!!!!!!!
qaws [65]

Answer:

x = - 6

Step-by-step explanation:

Given that y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = - 9 when x = 3, thus

k = \frac{y}{x} = \frac{-9}{3} = - 3

y = - 3x ← equation of variation

When y = 18, then

18 = - 3x ( divide both sides by - 3 )

x = - 6

5 0
3 years ago
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