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2 years ago

Simplify the expression.

Mathematics

1 answer:

Naddika [18.5K]2 years ago

6 0

Answer:

Step-by-step explanation:

((7x-4)^2) - (7x-4)(7x-4) + 3

(7x-4)(7x-4) is 7x-4^2

So its (7x-4)^2 - (7x-4)^2 + 3

(7x-4)^2 cancel out.

Answer is 3

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Miguel bought 2 1/4 pounds of hamburgers,1 1/5 pounds of sliced turkey ,and 2 pounds of cheese.what was the total weight of all

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the answer you are looking for is 5 9/20 pounds

sorry but it as to be twenty character

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3 years ago

The manager of a store that specializes in selling tea decides to experiment with a new blend. She will mix some Earl Grey tea t

marishachu [46]

Let us say that:

x = mass from Earl Grey Tea

y = mass from Orange Pekoe Tea

So that:

x + y = 600

and that:

6 x + 4 y = 4.5 * 600

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Answer:

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4 years ago

The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among

jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(d) The event is not unusual.

Step-by-step explanation:

Let X = number of households watching the show.

The probability of the random variable x is, P (X) = p = 0.18.

The sample selected for the survey is of size, n = 14

The random variable X follows a Binomial distribution with parameter n = 14 and p = 0.18.

The probability of a Binomial distribution is computed using the formula:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...$

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

$P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062$

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-0.062\\=0.938$

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

$={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253$

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

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This probability value is not low.

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4 years ago

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Answer:

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Answer:

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Step-by-step explanation:

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2 years ago