(-3, 3 ) --------> This is for the first coordinate(Dot) on the line.
(-2, 1 ) ---------> This is for the 2nd coordinate on the line.
I hope this helped :)
Answer:
Part 1. He would need to sell 8 Cars
Part 2. He would need to sell at least 15 cars
Part 3. 64,800 Would be your minimum value
Step-by-step explanation:
Part 1:
Start with x = the number of cars that he sells. So 250x +2400 =4400
250(8)+2400=4400
Part 2.
Same equation but you are looking for 6000 dollars or right over.
250(14)+2400=5900
So you would need it to be 15 cars, 250(15)+2400=6150
Part 3.
You we need to get the value for 12 cars, so
250(12)+2400=5400 then multiply that by 12 for a year
5400*12=64,800 Would be your minimum value
Is C 0.015? If so, then C, because if you imagine all of the numbers to the right as whole numbers, you get, in order from least to greatest, c, a, d, b. C is the answer.
Answer:
0.1384
Step-by-step explanation:
Using binomial probability:
P = nCr p^r q^(n-r)
where n is the number of trials,
r is the number of successes,
p is the probability of success,
and q is the probability of failure (1-p).
Given n = 25, r = 4, p = 0.10, and q = 0.90:
P = ₂₅C₄ (0.10)⁴ (0.90)²⁵⁻⁴
P = 12650 (0.10)⁴ (0.90)²¹
P = 0.1384