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My name is Ann [436]
3 years ago
8

If a photo measuring 4 inches by 6 inches is placed in a photo frame that is 2 inches wide all around, what percent of the frame

d photo is the photo itself?
Mathematics
2 answers:
BARSIC [14]3 years ago
8 0
It would be 2 by 2 in inches as the frame can only fit that much , which the area framed would be 4 inches as you multiply 2×2=4
lbvjy [14]3 years ago
8 0

Answer:

Percentage of the photo = 50%

Step-by-step explanation:

Given that the measurement of the photo is 4 inches by 6 inches and the measurement of the photo frame is 2 inches wide all around, it simply implies that is measurement of the photo frame is (4inches + 2inches) by (6 inches + 2inches). I.e 6inches by 8inches

To find the percentage of the photo itself, let find the area of the photo and that of the frame

Area of photo = 4 inches x 6 inches = 24inches²

Area of photo = 6 inches x 8 inches = 48inches²

Percentage of the photo = area covered by the photo / area covered by the frame x100

Percentage of the photo = 24/48 * 100

Percentage of the photo = 50%

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Your cousin plays point guard for her community basketball team. When she plays in a game, four out of every seven baskets she s
bearhunter [10]

Answer:

12

Step-by-step explanation:

count to 69 and you got 12 lay ups

5 0
2 years ago
Read 2 more answers
Provide an example of optimization problem
Mashutka [201]

Answer:

a. Convex solutions ,GO Methods

b. market efficiency

Explanation :

Step-by-step explanation:

A globally optimal solution is one where there are no other feasible solutions with better objective function values. A locally optimal solution is one where there are no other feasible solutions "in the vicinity" with better objective function values. You can picture this as a point at the top of a "peak" or at the bottom of a "valley" which may be formed by the objective function and/or the constraints -- but there may be a higher peak or a deeper valley far away from the current point.

In convex optimization problems, a locally optimal solution is also globally optimal. These include LP problems; QP problems where the objective is positive definite (if minimizing; negative definite if maximizing); and NLP problems where the objective is a convex function (if minimizing; concave if maximizing) and the constraints form a convex set. But many nonlinear problems are non-convex and are likely to have multiple locally optimal solutions, as in the chart below. (Click the chart to see a full-size image.) These problems are intrinsically very difficult to solve; and the time required to solve these problems to increases rapidly with the number of variables and constraints.

GO Methods

Multistart methods are a popular way to seek globally optimal solutions with the aid of a "classical" smooth nonlinear solver (that by itself finds only locally optimal solutions). The basic idea here is to automatically start the nonlinear Solver from randomly selected starting points, reaching different locally optimal solutions, then select the best of these as the proposed globally optimal solution. Multistart methods have a limited guarantee that (given certain assumptions about the problem) they will "converge in probability" to a globally optimal solution. This means that as the number of runs of the nonlinear Solver increases, the probability that the globally optimal solution has been found also increases towards 100%.

Where Multistart methods rely on random sampling of starting points, Continuous Branch and Bound methods are designed to systematically subdivide the feasible region into successively smaller subregions, and find locally optimal solutions in each subregion. The best of the locally optimally solutions is proposed as the globally optimal solution. Continuous Branch and Bound methods have a theoretical guarantee of convergence to the globally optimal solution, but this guarantee usually cannot be realized in a reasonable amount of computing time, for problems of more than a small number of variables. Hence many Continuous Branch and Bound methods also use some kind of random or statistical sampling to improve performance.

Genetic Algorithms, Tabu Search and Scatter Search are designed to find "good" solutions to nonsmooth optimization problems, but they can also be applied to smooth nonlinear problems to seek a globally optimal solution. They are often effective at finding better solutions than a "classic" smooth nonlinear solver alone, but they usually take much more computing time, and they offer no guarantees of convergence, or tests for having reached the globally optimal solution.

5 0
3 years ago
The manufacturer of a CD player has found that the revenue R​ (in dollars) is Upper R (p )equals negative 5 p squared plus 1 com
AleksAgata [21]

Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

Step-by-step explanation:

The revenue function is given as:

R(p) = -5p^2 + 1550p

where p is unit price in dollars.

First, we differentiate R(p) with respect to p, to get,

\dfrac{d(R(p))}{dp} = \dfrac{d(-5p^2 + 1550p)}{dp} = -10p + 1550

Equating the first derivative to zero, we get,

\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155

Again differentiation R(p), with respect to p, we get,

\dfrac{d^2(R(p))}{dp^2} = -10

At p = 155

\dfrac{d^2(R(p))}{dp^2} < 0

Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

R(155) = -5(155)^2 + 1550(155) = 120125

Thus, maximum revenue is $120125 that occurs when the unit price is $155.

6 0
3 years ago
Find m &lt; B. A)60 B)75 C)90 D)100
lozanna [386]
<B = <D = 60

answer
A. 60
7 0
3 years ago
Ivy is trying to manage the money she spends on lunch. Between eating out and buying groceries for bagged lunches, she wants to
mr_godi [17]

Answer:

The monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.

Step-by-step explanation:

This can be determined as follows

x = the amount of dollars spent at restaurants

y = the amount of dollars spent on groceries

Since Ivy decides that she wants to spend at least twice as much on bagged lunches as at restaurants, we have

y = 2x .................. (1)

Since Ivy wants to keep her weekly budget to less than $50, using the x and y, we have:

x + 2x < 50 ............................ (2)

We can now solve for x as follows:

3x + < 50

x < 50 / 3

x < 16.67

Substituting the x < 17 into equation (1) noting that Ivy wants to keep her weekly budget to less than $50, we have:

y < 2 * 16.67

y < 33.33

Therefore, the monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.

7 0
2 years ago
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