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ale4655 [162]
3 years ago
14

A car travels 312 miles in the same time that a motorcycle traveled 272. If the cars speed is 10mph more than the motorcycles, f

ind the speed of the car and the speed of the motorcycle.
Mathematics
1 answer:
dimaraw [331]3 years ago
3 0

Answer: speed of the car is 88 miles per hour

the speed of the motorcycle is 78 miles per hour

Step-by-step explanation:

Number of miles travelled by car = 312

Number of miles travelled by motorcycle = 272

Let x = speed of the car

Let y = speed of the motorcycle

If the car's speed is 10mph more than the motorcycle's, it means

x = y + 10 - - -- - - 1

Time taken for car to travel 312 miles is distance /speed = 312/x

Time taken for motorcycle to travel 272 miles is distance /speed = 272/y

The car travels 312 miles in the same time that a motorcycle traveled 272.

This means

312/x = 272/y

312y = 272x

y = 272x/312

Substituting y = 272x/312 into equation 1, it becomes

x = 272x/312 + 10

312x = 272x + 3120

312x-272x = 3120

40x = 3120

x = 3120/40 = 78 miles per hour

x = y + 10 = y + 78

x = 88 miles per hour

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I need help simplifying both of these. thank you!
4vir4ik [10]
<h3>Answer:</h3>
  1. -100x +100; 3
  2. 5x +81; 162
<h3>Step-by-step explanation:</h3>

The distributive property is your friend. It tells you ...

  a(b + c) = ab + ac

It can also be used to simplify the product of binomials (or other polynomials).

  (a +b)^2 = (a +b)(a +b) = a(a +b) + b(a +b) = a^2 +ab +ab +b^2

  (a +b)^2 = a^2 +2ab + b^2 . . . . . . . worth remembering

1. (x -10)^2 -x(x +80) = (x^2 -20x +100) +(-x^2 -80x)

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For the purposes of calculation, it can be easier to factor out 100:

  = 100 (1 -x)

Then for x = 0.97

  = 100(1 -0.97) = 100(0.03) = 3

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2. (2x +9)^2 -x(4x +31) = (4x^2 +36x +81) -4x^2 -31x = 5x +81

For x = 16.2, this is ...

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The purpose of the attachment is to show the evaluation is correct.

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2/9 is the answer broski
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VLD [36.1K]

See below for the terms, coefficients, and constants in the variable expressions

<h3>How to determine the terms, coefficients, and constants in the variable expressions?</h3>

To determine the terms, coefficients, and constants, we use the following instance:

ax + by + c

Where the variables are x and y

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Using the above as guide, we have:

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  • Coefficient: 2, 2 and 5
  • Constant 5

B) 34abx + 16y +1

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  • Coefficient: 34ab, 16
  • Constant: 1

C) st +4u + v

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  • Coefficient: 4

D) 14xy + 6

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Read more about terms, coefficients, and constants at:

brainly.com/question/14625487

#SPJ1

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