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ale4655 [162]
2 years ago
14

A car travels 312 miles in the same time that a motorcycle traveled 272. If the cars speed is 10mph more than the motorcycles, f

ind the speed of the car and the speed of the motorcycle.
Mathematics
1 answer:
dimaraw [331]2 years ago
3 0

Answer: speed of the car is 88 miles per hour

the speed of the motorcycle is 78 miles per hour

Step-by-step explanation:

Number of miles travelled by car = 312

Number of miles travelled by motorcycle = 272

Let x = speed of the car

Let y = speed of the motorcycle

If the car's speed is 10mph more than the motorcycle's, it means

x = y + 10 - - -- - - 1

Time taken for car to travel 312 miles is distance /speed = 312/x

Time taken for motorcycle to travel 272 miles is distance /speed = 272/y

The car travels 312 miles in the same time that a motorcycle traveled 272.

This means

312/x = 272/y

312y = 272x

y = 272x/312

Substituting y = 272x/312 into equation 1, it becomes

x = 272x/312 + 10

312x = 272x + 3120

312x-272x = 3120

40x = 3120

x = 3120/40 = 78 miles per hour

x = y + 10 = y + 78

x = 88 miles per hour

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tankabanditka [31]

The work done in pushing the box is 64000 lb-ft²/s²

<h3>How to calculate the work done by the person?</h3>

Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is

W = mgh where

  • m = mass of box = 40 lb,
  • g = acceleration due to gravity = 32 ft/s² and
  • h = height of incline = LsinФ where
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  • Ф = angle of incline = 30°

So, W = mgh

W = mgLsinФ

So, substituting the values of the variables into the equation, we have

W = mgLsinФ

W = 40 lb × 32 ft/s² × 100 ftsin30°

W = 1280 lb-ft/s² × 100 ft × 0.5

W = 1280 lb-ft/s² × 50 ft

W = 64000 lb-ft²/s²

So, the work done in pushing the box is 64000 lb-ft²/s²

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brainly.com/question/25970931

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3 0
2 years ago
PLEASE HELP LOOK AT PICTURE
Vladimir79 [104]
Hello! As e increases, the value of 3 will increase as well, making the answer A! Hope this helped you! :)
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3 years ago
$2000 was borrowed for 4 years with an interest rate of 3% compounded annually. What is the total amount owed at the end of the
kompoz [17]

Answer:

\$2,251.02  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the total amount owed  

P is the amount of money borrowed

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=4\ years\\ P=\$2,000\\ r=3\%=3/100=0.03\\n=1  

substitute in the formula above  

A=2,000*(1+\frac{0.03}{1})^{1*4}  

A=2,000*(1.03)^{4}  

A=\$2,251.02  

4 0
3 years ago
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We want to find the zeros of this polynomial p(x)= ( x^2-1)(x^2-5x+6)
Scrat [10]

Answer:

see explanation

Step-by-step explanation:

To find the zeros let p(x) = 0 , that is

(x² - 1)(x² - 5x + 6) = 0

Factorise each factor

x² - 1 ← is a difference of squares and factors as (x - 1)(x + 1)

x² - 5x + 6 = (x - 2)(x - 3), thus

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Equate each factor to zero and solve for x

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x + 1 = 0 ⇒ x = - 1

x - 2 = 0 ⇒ x = 2

x - 3 = 0 ⇒ x = 3

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The answer to your question is alphabetical order
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