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Lynna [10]
3 years ago
13

Which choice is equivalent to the quotient shown here for acceptable values of x?

Mathematics
1 answer:
Lunna [17]3 years ago
3 0
The correct answer is B hope this helped
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Why is 16 the answer to 10. x / 2 - 5 = 3? I need an answer today.
omeli [17]

Hi there!

\large\boxed{x = 16}

x / 2 - 5 = 3

Begin by adding 5 to both sides to isolate for x:

x / 2 - 5 + 5 = 3 + 5

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Multiply both sides by 2 to have "x" alone on the left-hand side:

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Find the width, height, and area of a 50 inch TV with a 16:9 aspect ratio
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3 years ago
[Sin A + Sin 3A + Sin 5A + Sin 7A]÷<br><br>[Cos A + Cos 3A + Cos 5A + Cos 7A]<br>=Tan 4A<br>​
Ainat [17]

Do the following rewrites:

sin(<em>x</em>) = sin(4<em>x</em> - 3<em>x</em>) = sin(4<em>x</em>) cos(3<em>x</em>) - cos(4<em>x</em>) sin(3<em>x</em>)

sin(7<em>x</em>) = sin(4<em>x</em> + 3<em>x</em>) = sin(4<em>x</em>) cos(3<em>x</em>) + cos(4<em>x</em>) sin(3<em>x</em>)

sin(3<em>x</em>) = sin(4<em>x</em> - <em>x</em>) = sin(4<em>x</em>) cos(<em>x</em>) - cos(4<em>x</em>) sin(<em>x</em>)

sin(5<em>x</em>) = sin(4<em>x</em> + <em>x</em>) = sin(4<em>x</em>) cos(<em>x</em>) + cos(4<em>x</em>) sin(<em>x</em>)

cos(<em>x</em>) = cos(4<em>x</em> - 3<em>x</em>) = cos(4<em>x</em>) cos(3<em>x</em>) + sin(4<em>x</em>) sin(3<em>x</em>)

cos(7<em>x</em>) = cos(4<em>x</em> + 3<em>x</em>) = cos(4<em>x</em>) cos(3<em>x</em>) - sin(4<em>x</em>) sin(3<em>x</em>)

cos(3<em>x</em>) = cos(4<em>x</em> - <em>x</em>) = cos(4<em>x</em>) cos(<em>x</em>) + sin(4<em>x</em>) sin(<em>x</em>)

cos(5<em>x</em>) = cos(4<em>x</em> + <em>x</em>) = cos(4<em>x</em>) cos(<em>x</em>) - sin(4<em>x</em>) sin(<em>x</em>)

So in the numerator, we have

sin(<em>x</em>) + sin(3<em>x</em>) + sin(5<em>x</em>) + sin(7<em>x</em>)

= 2 sin(4<em>x</em>) cos(3<em>x</em>) + 2 sin(4<em>x</em>) cos(<em>x</em>)

= 2 sin(4<em>x</em>) (cos(3<em>x</em>) + cos(<em>x</em>))

In the denominator,

cos(<em>x</em>) + cos(3<em>x</em>) + cos(5<em>x</em>) + cos(7<em>x</em>)

= 2 cos(4<em>x</em>) cos(3<em>x</em>) + 2 cos(4<em>x</em>) cos(<em>x</em>)

= 2 cos(4<em>x</em>) (cos(3<em>x</em>) + cos(<em>x</em>))

So we have

(sin(<em>x</em>) + sin(3<em>x</em>) + sin(5<em>x</em>) + sin(7<em>x</em>)) / (cos(<em>x</em>) + cos(3<em>x</em>) + cos(5<em>x</em>) + cos(7<em>x</em>))

= (2 sin(4<em>x</em>) (cos(3<em>x</em>) + cos(<em>x</em>))) / (2 cos(4<em>x</em>) (cos(3<em>x</em>) + cos(<em>x</em>)))

= sin(4<em>x</em>) / cos(4<em>x</em>)

= tan(4<em>x</em>)

QED

6 0
3 years ago
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