V=<span>π r^(2)h
you put the number in the place of the R and H</span>
Distance of each track are:
D₁ = 428.5 yd
D₂ = 436.35 yd
D₃ = 444.20 yd
D₄ = 452.05 yd
D₅ = 459.91 yd
D₆ = 467.76 yd
D₇ = 475.61 yd
D₈ = 483.47 yd
<u>Explanation:</u>
Given:
Track is divided into 8 lanes.
The length around each track is the two lengths of the rectangle plus the two lengths of the semi-circle with varying diameters.
Thus,

Starting from the innermost edge with a diameter of 60yd.
Each lane is 10/8 = 1.25yd
So, the diameter increases by 2(1.25) = 2.5 yd each lane going outward.
So, the distances are:
D₁ = 240 + π (60) → 428.5yd
D₂ = 240 + π(60 + 2.5) → 436.35 yd
D₃ = 240 + π(60 + 5) → 444.20 yd
D₄ = 240 + π(60 + 7.5) → 452.05 yd
D₅ = 240 + π(60 + 10) → 459.91 yd
D₆ = 24 + π(60 + 12.5) → 467.76 yd
D₇ = 240 + π(60 + 15) → 475.61 yd
D₈ = 240 + π(60 + 17.5) → 483.47 yd
Answer:
50 %
Step-by-step explanation:
From the diagram attached,
Percentage of total students that like watching television = [(WnR)/μ]×100......... Equation 1
The number of students that like watching television and reading (WnR) = 70
The total number of students (μ) = 40+20+70+10
The total number of students (μ) = 140
Substitute these values into equation 1
Percentage of total students that like watching television = (70/140)×100
Percentage of total students that like watching television = 1/2(100)
Percentage of total students that like watching television = 50 %
Geometric sequence is Exponential.
Geometric Recursive
a1=2
an=4 an-1
2,8,32,128,512
Answer- (-47)
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