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3 years ago

Find \tan(\beta)tan(β)tangent, left parenthesis, beta, right parenthesis in the triangle.

Mathematics

1 answer:

goldenfox [79]3 years ago

3 0

Answer:

the correct answer is C 8/15

Step-by-step explanation:

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3 years ago

Please ANSWER CORRECTLY BRAINIEST WILL BE GIVEN !!!!!

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4 years ago

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Find the missing side length leave your answers as radicals in the simplest form.

ira [324]

Answer:

Part 1) $x=\frac{10\sqrt{3}}{3}\ units$

Part 2) $y=5\ units$

Step-by-step explanation:

step 1

Find the value of x

In the right triangle of the figure

$sin(30^o)=\frac{(5\sqrt{3}/3)}{x}$ ---> opposite side angle of 30 degrees divided by the hypotenuse

Remember that

$sin(30^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{(5\sqrt{3}/3)}{x}$

solve for x

$x=\frac{5\sqrt{3}}{3}(2)$

$x=\frac{10\sqrt{3}}{3}\ units$

step 2

Find the value of y

In the right triangle of the figure

$cos(30^o)=\frac{y}{x}$ ---> adjacent side angle of 30 degrees divided by the hypotenuse

we have

$x=\frac{10\sqrt{3}}{3}\ units$

$cos(30^o)=\frac{\sqrt{3}}{2}$

substitute

$\frac{\sqrt{3}}{2}=\frac{y}{\frac{10\sqrt{3}}{3}}$

$y=(\frac{\sqrt{3}}{2})(\frac{10\sqrt{3}}{3})$

$y=5\ units$

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