A = 1/3 * s^2 * h where s is a side of the base and h is the height.
Answer:
ALL of the above
Step-by-step explanation:
I'm very positive this is right
on second thought...
<h2>
Greetings</h2>
Answer:
Graph number 1 and 3
Step-by-step explanation:
This is because continuous data is shown by drawing a line that means the pencil doesn't have to be taken off the page. Seeing as these two graphs are the only two with lines drawn, it means they are graph number 1 and 3.
<h2>Hope this helps!</h2>
Answer:
D. 13*3^x
Step-by-step explanation:
![3^x +4*3^x^+^1= \\3^x+4*3(3^x)=\\3^x(1+[4*3])=\\3^x(1+12)=\\3^x(13)=\\13*3^x](https://tex.z-dn.net/?f=3%5Ex%20%2B4%2A3%5Ex%5E%2B%5E1%3D%20%5C%5C3%5Ex%2B4%2A3%283%5Ex%29%3D%5C%5C3%5Ex%281%2B%5B4%2A3%5D%29%3D%5C%5C3%5Ex%281%2B12%29%3D%5C%5C3%5Ex%2813%29%3D%5C%5C13%2A3%5Ex)
Given:
The table of values is
Number of Students : 7 14 21 28
Number of Textbooks : 35 70 105 140
To find:
The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.
Solution:
The ratio of number of textbooks to number of students are




All the ratios of the two quantities are proportional and equivalent to the unit rate.
Let y be the number of textbooks and x be the number of students, then

Here, k=5.


Hence the rate of change is constant that is 5.