We are given with the equation y = x^3 -9x^2 - 16x +1. It is said that when the slope is 5, there are two points tangent to the graph. the slope is equal to the y'.y' = 3x2 -18x -16 = 5 3x2 -18x - 21 = 0x1 = 7 and x2 = -1The two points are (7,-209) and (-1,7)
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↪LINEAR EQUATIONS..
↪Since the equation given is
↪2x + 3y = 12
↪and the point given is (_,8)
to find the coordinate X or the abssicssa
↪we substitute the value of y = 8
↪therefore. ,, 2x +3 (8) =12
↪=》 2x + 24 = 12 =》 2x = 12-24 =》 2x = -12 =》 x = -6
↪thus , X = -6
↪points = ( -6 ,8)
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Answer: y = 12 - 3x
Step-by-step explanation:
Move "x" to the other side.
y = 12 - 3x
Answer:
x = 12
Step-by-step explanation:
Given a tangent and a secant from an external point to the circle, then
The square of the tangent is equal to the product of the external part and the entire secant, that is
x² = 6(6 + 18) = 6 × 24 = 144 ( take the square root of both sides )
x = 
= 12
Answer: 7 packs of cards
Step-by-step explanation:
<em>the best way to start is by writing down everything we know</em>
p = packs of cards; c = cost
6p + 5 = c
cost (c) = $47
<em>then plug in what you can</em>
6p + 5 = 47
<em>now solve using PEMDAS and properties of equality</em>
6p + 5 = 47
-5 -5 (do the opposite operation to cancel it out)
6p = 42
/6 /6 (make sure you do everything to both sides of the equation)
p = 7
hope this helped!
