Question

A circle has centre (0, 0) and it passes through the point (5, -3)

Answer 1

Answer:

radius = $\sqrt{34}$

Step-by-step explanation:

The radius r is the distance from the centre to a point on the circle.

Use the distance formula to calculate r

r = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (5, - 3)

r = $\sqrt{(5-0)^2+(- 3-0)^2}$

  = $\sqrt{5^2+(-3)^2}$

  = $\sqrt{25+9}$

  = $\sqrt{34}$