Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
12 The least common multiple of 6 and 4 is 12
Px + 12 = 17
px = 5
x = 5/p
ans) D
<span>The difference between the larger result and the smaller result was 10.
Suppose the 4 digits numbers are abcd and pqrs
Here, 1st Number is = 1000*a + 100*b + 10*c + d
and 2nd</span> Number is = 1000*ap + 100*q + 10*r + s
Then, since Kent made an error if 1 in tens columns and Harold added it correct, so the difference will be of 10 points.
Answer:
Option A is correct.
Step-by-step explanation:
Given an isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14. we have to find the area of isosceles trapezoid.
An isosceles trapezoid has base angles of 45° and bases of lengths 8 and 14.
From the figure attached , we can see an isosceles trapezoid ABCD,
AB = 8cm and CD=14cm
So we have to find the value of AE which is the height of Trapezoid in order to find area.
In ΔAED
⇒ 
∴ AE = DE =3cm
h=3cm, a=14cm, b=8cm
hence, 
Option A is correct.
