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2 years ago

7

Simplify 3x^2y^4 x 2x^6y

1 answer:

Feliz [49]2 years ago

8 0

Answer:

6x^8y^5

Step-by-step explanation:

(3)(2)= 6

add the exponents for the variables

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A rectangular skate park is 60 yards long and 50 yards wide

lawyer [7]

It is unclear what you want to do, but in the case where they give you the length and the width, it is most likely they are asking for either area or perimeter. For Area, it is length times width.
A = l x w
A = 60 yards x 50 yards
A = 3000 square yards.
For Perimeter of the rectangle, it is 2 of the lengths plus 2 of the widths.
P = 2 ( 60 yards ) + 2 ( 50 yards )
P = 120 yards + 100 yards
P = 220 yards
I hope this helps :-)

4 0

3 years ago

PLEASE HELP ME!!!

crimeas [40]

B=4676+10043 c=b-2160 answer equals b+c
I hope this is helpful I am trying not to say the exact answer but to teach you instead

4 0

3 years ago

The city of Orlando’s building a dog park in downtown Orlando dog park will be triangular shaped as shown on the coordinate plan

kiruha [24]

Answer:

Perimeter of the dog park = 15.4 yards

Step-by-step explanation:

Coordinates of the vertices of the given triangle are,

P(1, 2), Q(1, 6), R(-4, 2)

Since distance between the two points $(x_1, y_1)$ and $(x_2,y_2)$ is,

d = $\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Length of PQ = $\sqrt{(1-1)^2+(2-6)^2}$

PQ = 4

Length of PR = $\sqrt{(1+4)^2+(2-2)^2}$

PR = 5

Length of QR = $\sqrt{(1+4)^2+(6-2)^2}$

QR = $\sqrt{25+16}$

= $\sqrt{41}$

= 6.4 yards

Therefore, perimeter of the given triangle = PQ + QR + PR

= 4 + 6.4 + 5

= 15.4 yards

4 0

3 years ago

What is the area of a circle that has a radius of 3 miles?

mojhsa [17]

A=28.27 miles Sq
A= pie r2 = pie r.3 to 2nd power = 28.27 square miles

5 0

3 years ago

The playing life of a Sunshine radio is normally distributed with mean LaTeX: \muμ = 600 hours and standard deviation LaTeX: \si

Hitman42 [59]

Answer:

The probability that a radio selected at random will last from 600 to 700 hours is 0.3413

Step-by-step explanation:

The playing life of a Sunshine radio is normally distributed

Mean = $\mu = 600 hours$

Standard deviation = $\sigma = 100 hours$

We are supposed to find the probability that a radio selected at random will last from 600 to 700 hours i.e.P(600<x<700)

Formula: $Z= \frac{x-\mu}{\sigma}$

At x = 600

$Z= \frac{600-600}{100}$

Z=0

$P(X$

At x = 700

$Z= \frac{700-600}{100}$

Z=1

$P(X$

$P(600$

Hence the probability that a radio selected at random will last from 600 to 700 hours is 0.3413

8 0

3 years ago