Answer:
56.96% probability on a randomly selected team of 48 players that the average number of head hits per player is between 340 and 360 hits
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a single player:
For the sample mean(of 48 playes).
What is the probability on a randomly selected team of 48 players that the average number of head hits per player is between 340 and 360 hits?
This is the pvalue of Z when X = 360 subtracted by the pvalue of Z when X = 340. So
X = 360
By the Central Limit Theorem
has a pvalue of 0.6664
X = 340
has a pvalue of 0.0968
0.6664 - 0.0968 = 0.5696
56.96% probability on a randomly selected team of 48 players that the average number of head hits per player is between 340 and 360 hits