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4 years ago

Find the value of x. (Circles)

Mathematics

2 answers:

solong [7]4 years ago

8 0

Answer:

x =64.5

Step-by-step explanation:

Inscribed Angle = 1/2 Intercepted Arc

The total circle is 360 degrees

The arc is 360 - 113 - 118

arc =129

x = 1/2 (129)

x =64.5

Vaselesa [24]4 years ago

8 0

Answer:

64.5°

Step-by-step explanation:

Using the inscribed angle theorem here would help to find the value of x°.

The inscribed angle theorem states that an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle.

First find the arc PM. Write an equation to show that the measures of the following arcs: PQ, QM, and PM add up to 360°, since they span an entire circle. Then solve for the arc PM.

mPM + mPQ + mQM = 360°

mPM + 113° + 118° = 360°

mPM + 231 = 360°

mPM = 129°

Now, find m<Q. <Q is an inscribed angle that intercepts the arc PM, so use the Inscribed Angle Theorem.

m<Q = 1/2 * mHJ

= 1/2 ( 129 )

= 64.5°

X = 64.5 degrees.

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garik1379 [7]

Answer: 10$

Step-by-step explanation:

164 - 4x16 = 100

6 + 4 = 10

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3 years ago

4. As part of a promotion for a new type of cracker, free samples are offered to shoppers in a local supermarket. The probabilit

RUDIKE [14]

Answer:

For this case we need to check the conditions in order to use the normal approximation:

1) $np = 60*0.3= 18>10$

2) $n(1-p) = 60*(1-0.3)= 42>10$

Since both conditions are satisfied and the independence condition is assumed we can use the normal approximation given by:

$\hat p \sim N (\hat p, \sqrt{\frac{\hat p(1-\hat p)}{n}})$

The mean would be given by:

$\mu_{\hat p}=0.3$

And the deviation is given by:

$\sigma_{\hat p}= \sqrt{\frac{0.3*(1-0.3)}{60}}= 0.0592$

Step-by-step explanation:

For this case we know the following info:

n =60 represent the sample size

$\hat p = 0.3$ represent the estimated proportion of people that will buy a packet of crackers after tasting

For this case we need to check the conditions in order to use the normal approximation:

1) $np = 60*0.3= 18>10$

2) $n(1-p) = 60*(1-0.3)= 42>10$

Since both conditions are satisfied and the independence condition is assumed we can use the normal approximation given by:

$\hat p \sim N (\hat p, \sqrt{\frac{\hat p(1-\hat p)}{n}})$

The mean would be given by:

$\mu_{\hat p}=0.3$

And the deviation is given by:

$\sigma_{\hat p}= \sqrt{\frac{0.3*(1-0.3)}{60}}= 0.0592$

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3 years ago

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Vadim26 [7]

Substitute the values of a and b into the expression:
11 + 3 - 2
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14 - 2
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Hope this helps!

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3 years ago

Read 2 more answers

Lilli sent 40 text last week. This week the amount of text she sent decreased by 10%. How many text did she send this week?

gavmur [86]

Answer:

36 texts

Step-by-step explanation:

Last week = 40 texts

This week = 40 -10%of 40

= 40-4

=36 texts

Hope this helps you.

4 0

3 years ago