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2 years ago

90 units needed 8units per case

Mathematics

1 answer:

lisov135 [29]2 years ago

8 0

Answer: 90/8=11.25

Step-by-step explanation:

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Water flows from a tank with a rectangular base measuring 80cm by 70cm into another tank with a squarebase of side 60cm. If the

defon

Answer:

70cm

Step-by-step explanation:

Since, both of the tank posses the same quantity of water then there volume is the same thing

For rectangular base

Volume= (Lenght × breadth × hheight)

If we substitute values

Lenght= 80 cm

Breadth= 70 cm

height= 45 cm

Volume= 80cm × 70cm × 45cm

Volume= 252000cm^3

For square base

Volume= (side)^2 × height

side =60cm.

But volume of square base= volume of

rectangular base

252000cm^3= 60^2 × height

Height= (252000cm^3)/(60^2 )

Height= 70 cm

Hence, the second tank is 70 cm deep

4 0

2 years ago

Write an expression for F increased by 3

shutvik [7]

Answer:

The answer is F+3

Step-by-step explanation:

3 0

2 years ago

What expression is equivalent to 12x^4/4x^16 helpppp

adoni [48]

Answer: 48x/64

Work (assuming ^ is multiplication):

12x^4/4x^16

12x ^ 4x = 48x

4 ^ 16 = 64

3 0

1 year ago

Sean b= 5,79; c= 10,4,el angulo A= 54,46°, el angulo C mide ?

Rzqust [24]

Answer:

$C \approx 91.732^{\circ}$

Step-by-step explanation:

(This exercise is presented in Spanish and for that reason explanation will be held in such language)

El lado restante se determina por la Ley del Coseno:

$a = \sqrt{b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A}$

$a = \sqrt{5.79^{2}+10.4^{2}-2\cdot (5.79)\cdot (10.4)\cdot \cos 54.46^{\circ}}$

$a \approx 8.466$

Finalmente, el angulo C se halla por medio de la misma ley:

$\cos C = - \frac{c^{2}-a^{2}-b^{2}}{2\cdot a \cdot b}$

$\cos C = -\frac{10.4^{2}-8.466^{2}-5.79^{2}}{2\cdot (8.466)\cdot (5.79)}$

$\cos C = -0.030$

$C \approx 91.732^{\circ}$

3 0

2 years ago

Suppose Evan is trying to build a frame out of popsicle sticks x inches long. The frame will have length (2x – 3) and width of (

erik [133]

Answer:

The correct option is A) 3 square inches; $2x^2-7x+6$ .

Step-by-step explanation:

It is given that the length of the frame is (2x-3) and the width is (x-2)

The area of the rectangle is: $A=l\times w$

Where, A is the area l is the length and w is the width of the rectangle.

Put $l=(2x-3)$ and $w=(x-2)$ in the area of the rectangle.

$A=(2x-3)(x-2)\\A=2x^2-4x-3x+6\\A=2x^2-7x+6$

The area of the frame expressed as a polynomial is $2x^2-7x+6$ .

Now substitute x=3 in $A=2x^2-7x+6$ .

$A=2(3)^2-7(3)+6\\A=18-21+6\\A=3$

The area of the frame is 3 square inches.

Hence, the correct option is A) 3 square inches; $2x^2-7x+6$ .

8 0

2 years ago