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Oksana_A [137]
3 years ago
13

Which equation would best help solve this problem? Five added to 3 times a number is equal to 8 less than 5 times the number.

Mathematics
1 answer:
vitfil [10]3 years ago
4 0
\hbox{five added to 3 times a number = to 8 less than 5 times the number} \\\\ \implies \boxed{5+3x=8-5x}
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Help please The question is in the photo
Sergio039 [100]
I believe the answer to your question is 23
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2 years ago
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HELP I DONT GET IT!!!For the system below solve using linear combinations method 2a+3b=1 and -2a+b=11
Maksim231197 [3]
Linear combination method just means to add the equations so that one variable with cancel. In this case the a values are already set up so that they will cancel.
2a + 3b = 1
-2a + b = 11
4b = 12
b = 3

now put 3 back into either of the original equations and solve for a.
2a + 3(3) = 1
2a + 9 = 1
2a = -8
a = -4
(-4,3)
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3 years ago
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PLS HELP .........................
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Answer:

I believe the answer is C :)

Step-by-step explanation:

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3 years ago
Roger completed a probability experiment with a coin. He flipped the coin 32 times, and it landed on tails eight times. He looke
Vsevolod [243]
This is easy!
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Giving us 8/32
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6 0
3 years ago
The object on the right is made from a square-based pyramid joined to a cuboid.
spayn [35]

Answer:

Density of steel = 80.73 gm/cm^3

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

V_{Cuboid} = l \times w \times h

V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3

Density of Wood , D_{Cuboid}= 0.68g/cm^3

We know that formula of Density is:

Density = \dfrac{Weight}{Volume}

D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}

Putting the values:

W_{Cuboid} = 324 \times 0.68 = 220.32\ gm

Total weight = W_{Cuboid} + W_{Pyramid}

970 = 220.32 + W_{Pyramid}

W_{Pyramid} = 749.68 gm

Volume of pyramid is given as:

V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}

Base is a square with side 6 cm

V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3

Density of Steel/Pyramid:

D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3

5 0
3 years ago
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