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Oksana_A [137]
3 years ago
13

Which equation would best help solve this problem? Five added to 3 times a number is equal to 8 less than 5 times the number.

Mathematics
1 answer:
vitfil [10]3 years ago
4 0
\hbox{five added to 3 times a number = to 8 less than 5 times the number} \\\\ \implies \boxed{5+3x=8-5x}
You might be interested in
3. Which inequalities show a correct relationship between expressions?
igomit [66]

Answer: a and d

Step-by-step explanation:

First of all, we need to make a analysis of each letters:

a. factoring 32 = 2.2.2.2.2 = 2^{5}

2^{5}^{3} = 2^{15}

then,

16 = 2^{4}

but 2^{4}^{4} =2^{16}

in conclusion that, this inequality is correct

b. 27 =  3^{3}

this first situation is equal to  3^{9}

the second situation is:

81 =  3^{4}

and  3^{4}^{4} = 3^{16}

it's a mistake.

c. factoring 9: 9 = 3^{3}

3^{9} <  3^{5}

it's wrong.

d. factoring 8 = 2^{3}

factoring 32 =  2^{5}

2^{12} >  2^{10}

This is true.

Finally.. our correct answers is a and d.

3 0
3 years ago
Mary measured the heights of two different plants every day. Plant A was 1 inch tall when
seropon [69]

The heights of plant A and plant B will be equal on the day 8.

<h3>How to find the heights of the trees?</h3>

The height of the tree can be found as follows:

The equation for plant A can be described as follows:

y = 1 + 0.5x

where

x = number of days

y = height

The equation for plant B can be described as follows:

y = 3 + 0.25x

Therefore, for the height to be equal

1 + 0.5x =  3 + 0.25x

1 - 3 = 0.25x  - 0.5x

-2 = -0.25x

x = 2 / 0.25

x = 8 days

learn more on height here: brainly.com/question/16959984

#SPJ1

7 0
1 year ago
(b) Out of 200 students in an examination of class IX, 140 passed in Maths, 120 passed in Scien
iren [92.7K]

Answer:

n(U)=200

n(M)=140

n(S)=120

n(MuS)complement=40

n(MuS)=n(U)-n(MuS)complement

=200-40

=160

n(MnS)=n(M)+n(S)-n(MuS)

=140+120-160

=260-160

=100

3 0
3 years ago
Read 2 more answers
A random sample of 25 ACME employees showed the average number of vacation days taken during the year is 18.3 days with a standa
Norma-Jean [14]

Answer:

a) Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

b) df=n-1=25-1=24  

For this case the p value is given p_v = 0.0392

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.  

c) Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

Step-by-step explanation:

Data given and notation  

\bar X=18.3 represent the sample mean

s=3.72 represent the sample standard deviation

n=25 sample size  

\mu_o =15 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean for vacation days is higher than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: P-value  and conclusion

The first step is calculate the degrees of freedom, on this case:  

df=n-1=25-1=24  

For this case the p value is given p_v = 0.0392

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.  

Part c

Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

3 0
2 years ago
Simplify.
Alexus [3.1K]

Answer:

1/8

Step-by-step explanation:

To simplify the expression √3/√8, we can first simplify the square root terms by finding the prime factorization of each number under the square root. The prime factorization of 3 is 3, and the prime factorization of 8 is 2 * 2 * 2.

We can then rewrite the square root terms as follows:

√3/√8 = √(3) / √(2 * 2 * 2)

Next, we can use the property of square roots that says that the square root of a number is equal to the square root of each of its prime factors. This means that we can rewrite the square root term as follows:

√(3) / √(2 * 2 * 2) = √(3) / √(2) / √(2) / √(2)

Since the square root of a number is the same as the number itself, we can simplify the expression further by removing the square root symbols from the prime numbers 2:

√(3) / √(2) / √(2) / √(2) = √(3) / 2 / 2 / 2

Finally, we can use the rules of division to simplify the expression even further:

√(3) / 2 / 2 / 2 = √(3) / (2 * 2 * 2)

Since any number divided by itself is equal to 1, we can simplify the expression one last time to get our final answer:

√(3) / (2 * 2 * 2) = 1/2 * 1/2 * 1/2 = 1/8

Therefore, the simplified form of the expression √3/√8 is 1/8.

6 0
1 year ago
Read 2 more answers
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